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3 years ago

24% of 289 equals estimate using a rate per 100

2 answers:

8 0

69 because 24 times 289=6935 then you divided that by 100 because 24 was a percent and %=100 so 6,935 divided by 100 is 69.35 then you estimate so it would be 69

fenix001 [56]3 years ago

7 0

24/100*289=69.36 is the answer

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The statement below describes a situation in which opposite quantities combine to make zero:

77julia77 [94]

The answer is false. if the quantities combine to make zero

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4 years ago

Read 2 more answers

What’s number 2 4 and 5

erma4kov [3.2K]

Question 2.

(1,0) would go (-1,0)
(3,0) would go (-3,0)
(5,3) would go (-5,3)
(1,3) would go (-1,3)

question 4. (i think)

(0,-1) would go (-1,0)
(0,-2) would go (-2,0)
(-2,-2) would go (-2,2)
(2,0) would go (0,2)

question 5.

(-1,4) would go to (1,4)
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3 years ago

Radon is a gas produced when radium decays, and it can enter homes where it can be a health threat. Among 180 homes in Hyde Park

mylen [45]

Answer:

We are given that Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels. Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

Claim : the two towns have different rates of unsafe radon levels.

Let $p_1$ and $p_2$ be the rates of unsafe radon levels of Hyde Park and LaGrange respectively .

$H_0:p_1=p_2\\H_a:p_1\neq p_2$

Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels

So, $n_1=180, y_1=25$

Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

So, $n_2=230, y_2=50$

We will use Comparing Two Proportions

$\widehat{p_1}=\frac{y_1}{n_1}$

$\widehat{p_1}=\frac{25}{180}$

$\widehat{p_1}=0.1388$

$\widehat{p_2}=\frac{y_2}{n_2}$

$\widehat{p_2}=\frac{50}{230}$

$\widehat{p_2}=0.217$

$\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{25+50}{180+230}=0.1829$

Formula of test statistic : $\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}$

Substitute the values

test statistic : $\frac{0.138-0.217}{\sqrt{0.1829(1-0.1829)(\frac{1}{180}+\frac{1}{230})}}$

test statistic : −2.053

Refer the z table for p value

p value = 0.0202

α= 0.05

Since p value < α

So, we reject the null hypothesis that the two towns have same rates of unsafe radon levels.

So, Claim is true.

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4 years ago

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4 years ago