Answer:
x = ±2√15
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
x² = 60
<u>Step 2: Solve for </u><em><u>x</u></em>
- Square root both sides: x = ±√60
- Simplify: x = ±2√15
<u>Step 3: Check</u>
<em>Plug in both solutions of x to verify it's a solution.</em>
x = 2√15
- Substitute: (2√15)² = 60
- Evaluate: 4 · 15 = 60
- Multiply: 60 = 60
x = -2√15
- Substitute: (-2√15)² = 60
- Evaluate: 4 · 15 = 60
- Multiply: 60 = 60
Here we see that both solutions do indeed work.
∴ x = ±2√15 are both solutions to the equation.
Circumference of a circle is simply C = πd, d = diameter.
now, we know the diameter is 80, so C = π80, or just 80π.
(this is for fractions!!!!!!!!!!!!) 28/5 or 5 3/5
i think u just make it into 5.6/1 multiply by 10 which gets 56/10 and wala
but it's not simplified. 56 and 10 is divisible by 2 so u get 28/5 which is actually 5 3/5 (which is 5.6!!)
Up and down is vertical. At w = 0 there's a vertical asymptote.
