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3 years ago

6

A violin string has a standard length of 32.8 cm. It sounds the musical note A (440 Hz) when played without fingering. How far f

rom the end of the string should you place your finger to play the note C (523 Hz)?

1 answer:

Rus_ich [418]3 years ago

5 0

Answer:

The finger has to be placed at 5.25cm

Explanation:

The steps and appropriate formula in musical instrument is as shown in the attachment.

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Gretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s.

KIM [24]

Answer:

The velocity is $v = 4.76 \ m/s$

Explanation:

From the question we are told that

The first distance is $d_1 = 4.0 \ km = 4000 \ m$

The first speed is $v_1 = 5.0 \ m/s$

The second distance is $d_2 = 1.0 \ km = 1000 \ m$

The second speed is $v_2 = 4.0 \ m/s$

Generally the time taken for first distance is

$t_1 = \frac{d_1 }{v_1 }$

$t_1 = \frac{4000}{5}$

$t_1 = 800 \ s$

The time taken for second distance is

$t_1 = \frac{d_2 }{v_2 }$

$t_1 = \frac{1000}{4}$

$t_1 = 250 \ s$

The total time is mathematically represented as

$t = t_1 + t_2$

=> $t = 800 + 250$

=> $t = 1050 \ s$

Generally the constant velocity that would let her finish at the same time is mathematically represented as

$v = \frac{d_1 + d_2}{t }$

=> $v = \frac{4000 + 1000}{1050 }$

=> $v = 4.76 \ m/s$

7 0

4 years ago

how do scientists know that black holes exist A. by running experiments on the sun B. by observing objects and light around blac

NNADVOKAT [17]

Answer:

E. none of the above

Explanation:

I hope thats right

8 0

3 years ago

Read 2 more answers

A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg

slava [35]

Answer:

Explanation:

mass of first marble $m_1=m=0.015\ kg$

Initial velocity of the first marble $u_1=22.5\ m/s$

considering right side as positive

Mass of second marble

$m_2=m=0.015\ kg\\u_2=-18\ cm/s$

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. $v_1=-18\ cm/s$

considering $v_2$ be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

$e=\frac{v_2-v_1}{u_1-u_2}$

Putting values

$1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s$

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy = $0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J$

Final kinetic energy=

$0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J$

6 0

3 years ago

What is the period of a simple pendulum is its frequency is 20 Hz?

JulijaS [17]

Period = (1) / (frequency)

= (1) / (20/sec)

= 1/20 sec

5 0

4 years ago

In a physics lab, a 60-kg student runs up a 2.0-meter tall flight of stairs in 1.5 seconds. The work done to get to the top is 1

tester [92]

<span>The student's power rating is approximately 800W.
</span>
Power is the rate of doing work. Its SI unit is Watt. 1 W = 1J/sec

Given: <span>The work done to get to the top is 1200 Joules
</span>
Time = 1.5 seconds.

Power = $\frac{work done}{time} 
= \frac{1200J}{1.5 sec} 
= 800J/sec 
= 800W$

3 0

4 years ago