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nasty-shy [4]
3 years ago
7

How did new technology such as the telescope and new theories such as Pascal's Law laid the foundation of the Scientific Revolut

ion? *
Physics
1 answer:
AfilCa [17]3 years ago
4 0

Answer:

"Scientists used them to create new theories"

Explanation:

The Scientific Revolution was a sequence of actions that manifest the development of contemporary science through the early contemporary period, when advances in mathematics, physics, astronomy, biology and chemistry altered the opinions of civilization around nature. The scientific revolution denotes to the quick developments in European scientific, mathematical, and political assumed, grounded on a new philosophy of experimentation and a belief in growth that defined Europe in the 16th and 17th centuries.

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which energy transfers are used in the electric coil of a baseboard heater? A)conduction and radiation B)convection and radiatio
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conduction and radiation

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In a certain physics experiment, carts run along a frictionless, level track. Cart A is 1 kg and Cart B is 2 kg. Initially cart
timofeeve [1]

Answer:v=-\frac{11}{3} m/s \left

Explanation:

Given

Mass of car A\left ( m_a\right )=1 kg

Mass of car B\left ( m_b\right )=2 kg

velocity of cart A=3 m/s

velocity of cart B=-7 m/s

Conserving momentum

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3 years ago
4. AN OBJECT INCREASES ITS VELOCITY
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7 0
3 years ago
A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the
ExtremeBDS [4]

Answer:

a) v_{0y} = 9.72 m/s

b) v_{0x} = 20.85 m/s

c) t = 2.01 s

d) h_{max} = 4.82 m

Explanation:

a) The initial vertical velocity is given by:

v_{0y} = v*sin(\theta)

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

v_{0y} = 23 m/s*sin(25) = 9.72 m/s

b) The initial horizontal velocity can be calculated as follows:

v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s

c) The flight time can be calculated using the following equation:

v_{0x} = \frac{x}{t}

Where:

x: is the total distance = 42 m

t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s

d) The maximum height is given by:

v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}

Where:

v_{fy}: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m

I hope it helps you!                                  

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3 years ago
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