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andrew-mc [135]
3 years ago
13

Solve 9-2(2x+1)-(5x+6)= -8x+5-x

Mathematics
2 answers:
blsea [12.9K]3 years ago
8 0

the answer should be 1=5 unless you are in a really advanced class which the answer would be    x∈∅

sergey [27]3 years ago
4 0

The answer is -5 x - 2 (2 x + 1) + 3 = 5 - 9 x . Just combine all like terms, and then you have your answer!

Hope this helps! :D



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Directions: Graph each equation by using the y-intercept and slope( make sure too show your work)
vova2212 [387]

Given:

The equation of a linear function is:

y=-\dfrac{2}{3}x-1

To find:

The y-intercept and slope of the given equation, then draw the graph of the equation.

Solution:

Slope intercept form of a line is:

y=mx+b             ...(i)

Where, m is the slope and b is the y-intercept

We have,

y=-\dfrac{2}{3}x-1        ...(ii)

On comparing (i) and (ii), we get

m=-\dfrac{2}{3}

b=-1

Therefore, the y-intercept is -1 and the slope of the line is -\dfrac{2}{3}.

It means the graph intersect the y-axis at point (0,-1) and having slope -\dfrac{2}{3}. So, the graph of the equation is shown below.

4 0
3 years ago
WILL GIVE BRAINLIEST!! DUE IN A FEW MIN. PLEASE ANSWER CORRECTLY
Alekssandra [29.7K]

Answer:

y=3.5x+4; A(_,5) B(10,_)

Step-by-step explanation:

.Find point A: Substitute y value given, solve for x:

.

5=3.5x+4

1=3.5x

1/3.5=x

0.2857=x

.

Point A=(0.2857,5)

.

Find point B: Substitute x value given, solve for y:

.

y=3.5(10)+4

y=35+4

y=39

.

Point B=(10,39)

 

.

Slope:

In slope intercept form y=mx+b, m=slope

.

Slope=m=3.5

.

The others are done the same way.

5 0
3 years ago
Find the endpoint P of a line segment whose midpoint Q lies at (5, -10) and whose other endpoint lies at (-8, -4). Write it as a
blondinia [14]
P is (18, -16)

to find the answer, u would solve it in reverse order of the midpoint formula by first doing the x-values:

5(2)= 10-(-8) = 18

and then the same to y-values:

-10(2)= (-20)-(-4) = -16

to get:

(18, -16)
8 0
4 years ago
Help D: log3 x^6 =12 <br>find x
Zielflug [23.3K]

\log_ab=c\iff a^c=b\qquad(*)\\\\\log_ab^c=c\cdot\log_ab\qquad(**)\\\\---------------------\\\\\log_3x^6=12\qquad\text{use}\ (**)\\\\6\log_3x=12\qquad\text{divide both sides by 6}\\\\\log_3x=2\qquad\text{Use}\ (*)\\\\3^2=x\to\boxed{x=9}

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what is another way to write 297.3. Fill in: 2hundreds, 9tens, 5 ones + __________tenths I tried 2.3, but was told that was inco
Schach [20]
Maybe it is 23 tenths ???
7 0
3 years ago
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