Answer:
41.15
Step-by-step explanation:
41.15
R = x(A + B) solve for B
B = (R-A)/X
3.7÷1.1=3.36363636363636
The place values to the right of the decimal are tenths, hundredths, thousandths, ten-thousandths, and so on.
So the answer to the nearest hundredth is: 3.36
Because the number to the right is below 5, we keep it the same. If it were 5 or above, we would round the 3 to a 4.
Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Fail the test.
- Event B: Unfit.
The probability of <u>failing the test</u> is composed by:
- 46% of 37%(are fit).
- 100% of 63%(not fit).
Hence:

The probability of both failing the test and being unfit is:

Hence, the conditional probability is:

0.7873 = 78.73% probability that Mona was justifiably dropped.
A similar problem is given at brainly.com/question/14398287