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Eddi Din [679]
3 years ago
15

(1, 72), (3,66), (5, 53), (7, 40), (9, 34)

Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

<em>y = </em>-\frac{11}{2}<em> x + </em>\frac{159}{2}<em> </em>

Step-by-step explanation:

(1, 74)

(3, 63)

m = (63 - 74) / (3 - 1) = -\frac{11}{2}

y - 74 = -\frac{11}{2} (x - 1)

<em>y = </em>-\frac{11}{2}<em> x + </em>\frac{159}{2}<em> </em>

You might be interested in
If the area of a rectangle is 12cm2 what could its length be and its width?
lawyer [7]
Hello, 

We know that th formula for the area of a rectangle is: A=b*h
Now, the problem in this excercise is that there is no restriction on the values that b and h can take, so, they can take any value provided that it meets:  b*h=12 cm^{2}
for example:
lenght=  \frac{12}{3}cm \,\,\,\,\,\,and\,\,\,\,width= 3 cm \\  \\ A=\frac{12}{3}cm*3cm \\ A=12 cm^{2}

But if they can only take intenger values, what we have to do is to descompose 12, and then we can analyze the possible solutions.

12   |  2
  6   |  2
  3   |  3
  1

12= 2 *2*3

first option:
12=4*3

Answer: lenght= 4cm   and   width= 3cm  or vice versa

second option:
12=2*6

Answer: lenght= 6cm   and   width= 2cm  <span>or vice versa</span>
7 0
3 years ago
Indicate the method you would use
FinnZ [79.3K]

Answer:

correct choice is 1st option

Step-by-step explanation:

Two given triangles have two pairs of congruent sides: one pair of length 7 units and second pair of length 8 units. The third side is common, i.e the lengths of third sides are equal too.

Use SSS theorem that states that if three sides of one triangle are congruent to three sides of another triangle, then these two triangles are congruent.

Thus, given triangles are congruent by SSS theorem.



7 0
3 years ago
Factor the following polynomial completely. Start by getting the GCF of the polynomial. 2x^3-18x
Vesna [10]

Answer:

GCF: 2x

Factored: 2x(x+3)(x-3)

Step-by-step explanation:

6 0
3 years ago
Ben, Tim, and Sam have to do a certain job. Ben can finish the job in 5 hours. Tim can finish the job in 6 hours. Sam can finish
Brut [27]

x is 7.5 hours

Step-by-step explanation:

Ben, Tim, and Sam have to do a certain job

  • Ben can finish the job in 5 hours
  • Tim can finish the job in 6 hours
  • Sam can finish the job in x hours
  • The three of them can finish the job in 2 hours if they work together

We need to find x

∵ Ben can finish the job in 5 hours

∴ The rate of Ben = \frac{1}{5}

∵ Tim can finish the job in 6 hours

∴ The rate of Tim = \frac{1}{6}

∵ Sam can finish the job in x hours

∴ The rate of Sam = \frac{1}{x}

They will working together to finish the job in two hours, that means the sum of their rate is equal to 1/2

∵ They can finish the job in 2 hours if they work together

∴ \frac{1}{5}+\frac{1}{6}+\frac{1}{x}=\frac{1}{2}

To add the fractions find the LCM for all denominators to make all fractions with same denominators

∵ The LCM of 5, 6 ans x is (5 × 6 × x) = 30 x,

- Divide it by each denominator to find the new numerators

∵ 30 x ÷ 5 = 6 x , 30 x ÷ 6 = 5 x , 30 x ÷ x = 30

- Change all the denominators to 30 x and then write the new

   numerators of each fraction

∴ \frac{6x}{30x}+\frac{5x}{30x}+\frac{30}{30x}=\frac{1}{2}

Add the numerators and put the sum over 30 x

∵ \frac{11x+30}{30x}=\frac{1}{2}

- By using cross multiplication

∴ 2(11 x + 30) = 1(30 x)

- Simplify the both sides

∴ 22 x + 60 = 30 x

- Subtract 22 x from both sides

∴ 60 = 8 x

- Divide both sides by 8

∴ 7.5 = x

∴ The value of x is 7.5 hours

x is 7.5 hours

Learn more:

You can learn more about the word problems in brainly.com/question/10712420

#LearnwithBrainly

5 0
3 years ago
The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.3 days and a standard de
inna [77]

Answer:

<em>The probability of spending between 4 and 7 days in recovery</em>

<em>P(4≤x≤7) = 0.5445</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let    x₁ = 4

Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65

Let    x₂ = 7

Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85

<u><em>Step(ii):-</em></u>

<u><em>The probability of spending between 4 and 7 days in recovery</em></u>

<em>P(4≤x≤7) = P(-0.65≤Z≤0.85)</em>

<em>              =  P(Z≤0.85) - P(Z≤-0.65)</em>

<em>             = 0.5 + A( 0.85) - ( 0.5 - A(-0.65) </em>

<em>             = 0.5 + A( 0.85) -  0.5 +A(0.65)   ( ∵A(-0.65) = A(0.65)</em>

<em>            =   A(0.85) + A(0.65)</em>

<em>           = 0.3023 + 0.2422</em>

<em>          = 0.5445</em>

<u><em>Final answer:</em></u><em>-</em>

<em>The probability of spending between 4 and 7 days in recovery</em>

<em>P(4≤x≤7) = 0.5445</em>

<em>            </em>

6 0
3 years ago
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