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3 years ago

(1, 72), (3,66), (5, 53), (7, 40), (9, 34)

Mathematics

1 answer:

IceJOKER [234]3 years ago

7 0

Answer:

y = $-\frac{11}{2}$ x + $\frac{159}{2}$

Step-by-step explanation:

(1, 74)

(3, 63)

m = (63 - 74) / (3 - 1) = $-\frac{11}{2}$

y - 74 = $-\frac{11}{2}$ (x - 1)

y =  $-\frac{11}{2}$  x +  $\frac{159}{2}$  

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Answer:

Step-by-step explanation:

The formula of volume of cone is

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V=\frac{1}{3}\pi r^{2} h

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Read more on Brainly.com - brainly.com/question/9177514#readmore

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3 years ago

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3 years ago

9. Given the point (6,-8) values of the six trig function.

lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

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∆AOB is a right triangle.

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$\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}$

10. cot θ = -(√3)/2

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∆AOB is a right triangle.

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OB = √7

$\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}$

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Answer:

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Hope this helps!

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