B. real number and c. rational number
Answer:
Step-by-step explanation:
If Thaddeus drives the whole 16 hours, the distance between them is ...
distance = speed · time
distance = 20 mi/h · 16 h
distance = 320 miles.
It is 45 miles more than that. For each hour that Ian drives, their separation distance increases by (25 mph -20 mph)·(1 h) = 5 mi. Then Ian must have driven ...
(45 mi)/(5 mi/h) = 9 h
The rest of the 16 hours is the time that Thaddeus drove: 7 hours.
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Let x represent the time Ian drives. Then 16-x is the time Thaddeus drives. Their total distance driven is ...
distance = speed · time
365 mi = (25 mi/h)(x) + (20 mi/h)(16 h -x)
45 mi = (5 mi/h)(x) . . . . . . . . subtract 320 miles, collect terms
(45 mi)/(5 mi/h) = x = 9 h . . . . . . divide by the coefficient of x
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<em>Comment on the solution</em>
You may notice a similarity between the solution of this equation and the verbal discussion above. (That is intentional.) It works well to let a variable represent the amount of the highest contributor. Here, that is Ian's time, since he is driving at the fastest speed.
Answer:
112 :D hope this helps
Step-by-step explanation:
112
Answer:
12. 11/18-1/6=4/9
13. 2/7+2/5=24/35
14. 3/4-3/10=9/20
Step-by-step explanation:
12. 11/18-1/6
11/18-1/6=11/18-(1/6)*(3/3)
11/18-1/6=11/18-(1*3)/(6*3)
11/18-1/6=11/18-3/18
11/18-1/6=(11-3)/18
11/18-1/6=8/18
Dividing the numerator and denominator of the fraction on the right side of the equation by 2:
11/18-1/6=(8/2)/(18/2)
11/18-1/6=4/9
13. 2/7+2/5
2/7+2/5=(2/7)*(5/5)+(2/5)*(7/7)
2/7+2/5=(2*5)/(7*5)+(2*7)/(5*7)
2/7+2/5=10/35+14/35
2/7+2/5=(10+14)/35
2/7+2/5=24/35
14. 3/4-3/10
3/4-3/10=(3/4)*(5/5)-(3/10)*(2/2)
3/4-3/10=(3*5)/(4*5)-(3*2)/(10*2)
3/4-3/10=15/20-6/20
3/4-3/10=(15-6)/20
3/4-3/10=9/20
Let's say n = the unknown number
then, 3n-25 would be your answer
