This would be much, much, much easier if you told us
what numbers you do have on each side of the scale now.
The idea (probably) is that the scale is balanced when
the numbers add up to the same amount on both sides.
So you need to put some numbers in the blanks that will either
add more to the side that has less, or subtract some from the side
that has more, to make both sides equal.
Answer:
Step-by-step explanation:
1. (sq root of) a^2 if a>0 => √(a^2) = ±a
2. (sq root of) 36x^2 if a>0 => ±6x
Answer:
If it's perimeter, then its 23. If it's multiplying, then it's 810.
Step-by-step explanation: Please brainliest if possible!
Hello,
The formula for finding the area of a circular region is:

then:

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

Now we can find its area:
![A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)](https://tex.z-dn.net/?f=A_%7B2%7D%3D2%2A%20%5Cfrac%7Bb%2Ah%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20A_%7B2%7D%3D%20%5Br%2Asen%2840%29%5D%5Br%2Acos%2840%29%5D%5C%5C%20%20%5C%5CA_%7B2%7D%3D%20r%5E%7B2%7D%2Asen%2840%29%2Acos%2840%29)
The subtraction of the two areas is 100cm^2, then:
Answer: r= 1.59cm