Vertex form is f(x) = a(x - b)^2 + c where the vertex is (b, c) and a is some constant.
So for the first part we have f(x) = a(x + 6)^2 - 1
for root -9:- a( -9+6)^2 - 1 = 0
9a - 1 = 0 , a = 1/9
The other 3 are derived in the same way.
so required equation is f(x) = (1/9)(x + 6)^2 - 1
Need help in this question asap srry i need points
#7 is B!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Ok
Step-by-step explanation:
What grade are the questions from?
Step-by-step explanation:
Your problem → 5y+5/2 / 25y-20/40y^2-32y
5y+5/2÷25y-20/40y^2-32y
=5⋅y+5/2÷25×y-20/40×y^2-32×y
=5y+5/2÷25×y-20/40×y^2-32y
=5y+5/2×1/25×y-20/40×y^2-32y
=5y+y/10-20/40×y^2-32y
=5y+y/10-y^2/2-32y
=5y×10+y-y^2×5-32y×10 ÷ 10
=50y+y-5y2-320y ÷ 10
= -269y-5y^2 / 10
