3 years ago

Equation of a circle whose circle is at the origin and whose radius is 16

1 answer:

4 0

Equation of the circle with centre at the origin and radius 'R' is
x²+y²=R² Hence When R= 16, the required equation is 
x²+y²=16² 
i.e. x²+y²=256

You might be interested in

What is the equation of the line that passes through the point

snow_lady [41]

Answer:

$3x-2y=2$

Step-by-step explanation:

The equation of line having slope $\frac{3}{2}$ and passing through $(-4,-7)$ .

$The\ equation\ of\ line\ is\ given\ by\ y=mx+c\ where\ m\ is\ the\ slope\ of\ line.\\\\Here\ m=\frac{3}{2}\\\\Equation\ y=\frac{3}{2}x+c\\\\Line\ passes\ through\ (-4,-7),\ it\ will\ satisfy\ the\ equation\ of\ line.\\\\-7=\frac{3}{2}\times (-4)+c\\\\-7=-6+c\\\\c=-7+6\\\\c=-1\\\\y=\frac{3}{2}x-1\\\\2y=3x-2\\\\3x-2y=2$