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victus00 [196]
3 years ago
5

A company sells cereal in two different-sized boxes: a 17-ounce box for $2.89, and a 24-ounce box for $3.29. How do the unit pri

ces of the two boxes compare?
The smaller box is the better buy because it is approximately 1.4 cents cheaper per ounce.
The smaller box is the better buy because it is approximately 3.3 cents cheaper per ounce.
The larger box is the better buy because it is approximately 1.4 cents cheaper per ounce.
The larger box is the better buy because it is approximately 3.3 cents cheaper per ounce.
Mathematics
1 answer:
garik1379 [7]3 years ago
5 0

Answer: Last option.

Step-by-step explanation:

Let be "s" the unit price of the smaller box and "l"  the unit price of the larger box.

According to the information given in the exercise, the smaller one is a 17-ounce box which costs $2.89. Therefore, in order to find the value of "s", you need to divide  $2.89 by 17 ounces. This is:

s=\frac{2.89\ dollars}{17\ ounce}\\\\s=0.17\ \frac{dollars}{ounce}

You know that the larger box has 24 ounces and it costs $3.29.

Therefore, in order to find the value of "l", you need to divide  $3.29 by 24 ounces. This is:

l=\frac{3.29\ dollars}{24\ ounce}\\\\l=0.137\ \frac{dollars}{ounce}

Finally, find the difference:

0.17\ \frac{dollars}{ounce}-0.137\ \frac{dollars}{ounce}=0.033\ \frac{dollars}{ounce} or 3.3\ \frac{cents}{ounce}

Therefore, you can conclude that the larger box is better buy because it is approximately 3.3 cents cheaper per ounce.

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I would say 5 pounds for $12.95
Hope this helps!
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5y+30 5 complete the factoring ...?
krek1111 [17]
Well, I don't really understand if it is 30 or 305 because of the spacing but I'll answer both. If it is 5y+305, just divide the whole equation by 5 and it will look like this (<u>5y+305)</u>  then the factor would be 5(y+61)<u>
</u>                   5 
If it is 5y+30 it would be just in the same process, Divide the equation by 5 and the result will be 5(y+6).
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The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households
liq [111]

Answer:

Null hypothesis:\mu_{1}-\mu_{0}\leq 0

Alternative hypothesis:\mu_{1}-\mu_{2}>0

SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705

b) 2.70

t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850

b. 1.85

p_v =P(Z>1.85)=0.032

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

\bar X_{1}=164 represent the mean for the sample 1

\bar X_{2}=159 represent the mean for the sample 2

\sigma_{1}=12.5 represent the population standard deviation for the sample 1

s_{2}=9.25 represent the population standard deviation for the sample B2

n_{1}=35 sample size selected 1

n_{2}=30 sample size selected 2

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{0}\leq 0

Alternative hypothesis:\mu_{1}-\mu_{2}>0

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}

Replacing the values that we have we got:

SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850  

P-value

Since is a one side right tailed test the p value would be:

p_v =P(Z>1.85)=0.032

b. 0.03

Conclusion

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

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Answer:


Step-by-step explanation:

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