The van can carry 6 students and bus can carry 21 students.
Step-by-step explanation:
Given,
High School A: 12 vans and 11 buses with 303 students
High School B: 6 vans and 7 buses with 183 students
To find the number of students that a van and a bus can carry.
Let us take,
The van can carry x students and the bus can carry y students.
According to the problem,
12x+11y = 303 ------- (1)
6x+7y = 183 ------- (2)
Multiplying 2 with (2) and subtract (1) and (2) we get,
(12x+11y) - 2(6x+7y) = 303-2(183)
or, 12x+11y-12x-14y = 303-366
or, -3y = -63
or, y = 21
From (2) we get,
6x+7(21) = 183
or, 6x = 183-147
or, 6x = 36
or, x = 6
Hence,
The van can carry 6 students and bus can carry 21 students.
Answer:
d. $12.00 and up to $15.00
Step-by-step explanation:
The hourly earnings classes and their respective frequencies are presented bellow:
The least occurring class is the $12 to $15 with 10 occurrences.
Therefore, the limits of the class with the smallest frequency is d. $12.00 and up to $15.00
Let x = liters 20% solution to be added
then
.12(12) + .20x = .14(12+x)
.12(12) + .20x = .14(12+x)
1.44 + .20x = 1.68 + .14x
.20x = .24 + .14x
.06x = .24
x = 4 liters
Hope this helped!!
Answer:
The correct answer is second option 90 m³
Step-by-step explanation:
Formula:
Volume of prism = Base area * Height
Area of rectangle = length * breadth
From the figure we can see that height of prism = 5 in
Base is a rectangle with length = 6 in and breadth = 3 in
<u>To find the Base area
</u>
Area of rectangle= = length * breadth = 6 * 3 = 18
<u>To find the volume of prism</u>
Volume of prism = Base area * Height = 18 * 5 = 90 m³
Therefore the correct answer is second option 90 m³