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Alenkasestr [34]
3 years ago
10

What's the awnser to this

Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0
The answer is B

If x is equal to width, then 7*x would equal seven times tge width. 7x= length so length equals seven times the width.
meriva3 years ago
4 0
I'd definitely go with B. Let me know how it goes :)
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1.6/n = 1.2/20<br> What's the correct answer?
natita [175]

Answer:

n = 26 2/3

Step-by-step explanation:

Step 1: Cross-multiply.

  • (1.2) * (n) + 1.6*20
  • 1.2n =32

Step 2: Divide both sides by 1.2

  • 1.2n/1.2 = 32/1.2
  • n = 26\frac{2}{3}

Therefore, the answer is n = 26 2/3.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0
2 years ago
The circle has a radius of 11 cm. What is the area of the shaded sector? Use 3.14 for π, and round your answer to the nearest te
Temka [501]
379.9 cm 2 or 253 cm 2
3 0
2 years ago
Can someone help me with this ​
xeze [42]

Answer

So if you want to get the area of a parallelogram you should do length x width

So 3.7 x 12.5= 46.25

I’m sorry if this is a wrong answer but this is what the teacher told us

3 0
3 years ago
The product of complete numbers<br> (4, 6) and (5-6) is ?
alexdok [17]

Answer:

(38,9)

Step-by-step explanation:

4 0
2 years ago
Four circles of unit radius are drawn with centers $(1,0)$, $(-1,0)$, $(0,1)$, and $(0,-1)$. a circle with radius 2 is drawn wit
Reika [66]
Check the picture 1.

The regions contained in an odd number of these 5 circles are

the pink colored region, contained only in the circle with radius 2, 

and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.

So what we need to determine is the "area pink + area yellow".


Consider the second picture.

Let A2 be the area of the right isosceles triangle, and A1 be half of the yellow region.

the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.

A1=A_{sector}-A2= \frac{1}{4} \pi r^2- \frac{1}{2}.1.1= \frac{1}{4} \pi 1^2- \frac{1}{2}=  \frac{1}{4}\pi- \frac{1}{2}


Thus, the overall yellow region is 8A1=8(\frac{1}{4}\pi- \frac{1}{2})=2\pi-4


The purple area is:
 
Area of large circle - 4*(Area of 1 small circle) + yellow region.

(because subtracting all 4 small circles means that each of the 4 separate yellow regions have been subtracted twice)

A_{purple}=\pi.2^2-4(\pi.1^2)+2\pi-4=4\pi-4\pi+2\pi-4=2\pi-4


Finally, the total area is : 2\pi-4+2\pi-4=4\pi-8 (units squared) 



Answer:   6\pi-8    square units

6 0
3 years ago
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