Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
we know that
EB=ED+DB
ED=DB -----> given problem
Substitute the given values and solve for x
<em>Find the value of ED</em>
substitute the value of x
<em>Find the value of DB</em>
Remember that
ED=DB
therefore
<em>Find the value of EB</em>
EB=ED+DB
Step-by-step explanation:
2x+10=86+x
2x-x=86-10
x=76
I hope you understood :)
Answer:
D
Step-by-step explanation:
When dividing fractions, multiply the first number by the reciprocal of the second number
2/5 ÷ 1/3
First, find the reciprocal of the second number: 1/3
To find the reciprocal, flip the numerator (top number) and denominator (bottom number)
1/3-->3/1
Now, multiply 2/5 and 3/1
2/5 * 3/1
Multiply across the numerators and denominators
6/5
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
20+2N=52
now subtract 20 from each side, to get 2N alone
2N=32
now divide each side by 2
N=16
