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Annette [7]
3 years ago
10

4.06 Question 3

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

4c + 6a < = 120 ...4(20) + 6(6) = 116 <== correct

4c + 4a < = 100....4(20) + 4(6) = 104 <== incorrect

Step-by-step explanation:

defon3 years ago
7 0

Answer: No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100

hope this helps let me know if it's wrong.

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Solve for v<br> Simply as much as possible <br> 9v=16+v
qaws [65]

Answer:

v=2

Step-by-step explanation:

9v=16+v

9v-v=16

8v=16

v=16/8

v=2

8 0
3 years ago
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Please help, thank you.
irakobra [83]

Answer:

4:1 is first answer

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3 years ago
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The two lines y= 6x+15 and y= mx+4 intersect at x= -2. What is the y-coordinate of their intersection point
taurus [48]

Answer:

The y-coordinate of their intersection point is 3

That is y=3

Step-by-step explanation:

Given two lines are y=6x+15 and y=mx+4

Given that the two lines intersect at x=-2

To find the y coordinate of their intersection point :

Equating the two lines

6x+15=mx+4

6x+15-mx-4=0

6x-mx+11=0

(6-m)x+11=0

At x=-2  (6-m)x+11=0

(6-m)(-2)+11=0

(6-m)(-2)=-11

6-m=\frac{11}{2}

-m=\frac{11}{2}-6

-m=\frac{11-12}{2}

-m=\frac{-1}{2}

m=\frac{1}{2}

Substitute the value m=\frac{1}{2} in y=mx+4 we get

y=\frac{1}{2}x+4

At x=-2 y=\frac{1}{2}(-2)+4

=-1+4

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Therefore y=3

Therefore the y-coordinate of their intersection point is 3

7 0
3 years ago
2h divided by 15 equals 20
Lynna [10]
<span>(2*h)/15 = 20 // - 20

(2*h)/15-20 = 0

2/15*h-20 = 0 // + 20

2/15*h = 20 // : 2/15

h = 20/2/15

h = 150

h = 150</span>
8 0
3 years ago
The volume of a cone =13πr2h
xz_007 [3.2K]

Answer:

Volume of cone = 418.67 cm³ (Approx.)

Step-by-step explanation:

Given:

Radius of cone = 5 cm

Height of cone = 16 cm

Find:

Volume of cone

Computation:

Volume of cone = [1/3][π][r²][h]

Volume of cone = [1/3][3.14][5²][16]

Volume of cone = [1/3][3.14][25][16]

Volume of cone = [1/3][3.14][400]

Volume of cone = [1/3][1,256]

Volume of cone = 418.67 cm³ (Approx.)

8 0
3 years ago
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