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Annette [7]
3 years ago
10

4.06 Question 3

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

4c + 6a < = 120 ...4(20) + 6(6) = 116 <== correct

4c + 4a < = 100....4(20) + 4(6) = 104 <== incorrect

Step-by-step explanation:

defon3 years ago
7 0

Answer: No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100

hope this helps let me know if it's wrong.

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MrRa [10]

To find the unit price, divide the total price by the total weight.

4.60 / 2 = 2.30

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Best of Luck!

3 0
4 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
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Nataly [62]
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3 years ago
PLEASE ANSWER + BRAINLIEST !!!!<br><br> Find the indicated sum for the arithmetic series.
schepotkina [342]
Hello there,


I believe the answer would be 17×6 - 6(9+14)(6)/2 = 102 -414 = -312 but i am not 100% Sure!! Sorry if I am wrong!

Hope I helped
8 0
4 years ago
Find angle A and angle B..​
ExtremeBDS [4]

Step-by-step explanation:

\sf{\bold{\blue{\underline{\underline{Given}}}}}

\tt{\angle{c}=110°}

and,

\tt{BC=AC}

⠀⠀⠀⠀

\sf{\bold{\red{\underline{\underline{To\:Find}}}}}

☆Find the \angle{B} ~and~\angle{A}

\sf{\bold{\purple{\underline{\underline{Solution}}}}}

Here,

BC =AC

so,

⠀⠀⠀

\angle{A}=\angle{B}

we know that,

\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}

But \angle{C}=110°(Ģìvéñ)

so..

\angle{A}+\angle{B}+110°=180°

\angle{A}+\angle{A}+110°=180°

\because{\angle{A}=\angle{B} }

2\angle{A}=180°-110°

2\angle{A}=70°

\angle{A}=\dfrac{70°}{2}

\boxed{\orange{\angle{A}=35°}}

But...

\angle{A}=\angle{B}

soo,

\boxed{\orange{\angle{B}=35°}}

\sf{\bold{\green{\underline{\underline{Answer}}}}}

⠀⠀⠀⠀

\boxed{\green{\angle{A}=35°}}

\boxed{\green{\angle{B}=35°}}

7 0
3 years ago
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