<span>m= <span><span><span><span>−5/</span>3 </span></span></span></span><span> ,swnkadkjkkjmd,m,mdas</span>
<u>Additional requirements in figure</u> :-
Mark point :-
Draw a straight line from E to AB .
And the point line joins mark it as "F" .
It will generate quadrilateral FBCD.
we get to know In quadrilateral left angle is 90°
How ?
{
proof :
As three angles are given 90° So third angle will also be 90°
Reason:
→ Sum of interior angles = 2 (no. of angles - 2 × 180°
→Sum of interior angles = (4-2 × 180°)
→Sum of interior angles = (2 × 180°)
→Sum of interior angles = 360°
}
<u>✿</u><u>Now let the left angle be </u><u>x</u>
- 90° +90° + 90° + x = 360°
- 180° + 90° + x = 360°
- 270° + x = 360
- x = 360° - 270°
- x = 90°
<u>we know</u> :
Area of rectangle = Length × Breadth
STEPS :
- Area of rectangle = Length × Breadth
- Area of rectangle = 7 × 8
- Area of rectangle = 56 in²
<u>Now let's find EF</u> :
<u>To find A</u>
<u>F</u> :
<u>In triangle AFE</u>:
- EF is base of triangle
- A•F is height of triangle
We know :
<u>Area of triangle =(</u><u> </u><u>Height</u><u> </u><u>×</u><u> </u><u>Base)/2</u>
Steps :
- Area of triangle = (Height × Base)/2
- Area of triangle = (4 × 3)/2
- Area of triangle = 12/2
- Area of triangle = 6 in²
<u>To find area of figure</u> :
- Area of figure = Area of rectangle + Area of triangle
- Area of figure = 56 + 6
- Area of figure = 62 in²
______________________
~WindyMint
Here: 6y = 6x + 12
6y - 6x = 12
Divide by 6,
y - x = 2
Which is nothing but first equation!
In short, Your Answer would be: "Infinitely Many solutions"
[ As L.H.S = R.H.S ]
Hope this helps!
Answer:
(1238.845 ;1285.376)
Step-by-step explanation:
Conditions for constructing a confidence interval :
Data must be random
Distribution should be normal and independent ;
Based on the conditions above ; data meets initial conditions ;
C. I = sample mean ± margin of error
Given the data :
1241 1210 1267 1314 1211 1299 1246 1280 1291
Mean, xbar = Σx / n = 11359 / 9 = 1262.11
The standard deviation, s = [√Σ(x - xbar)²/n - 1]
Using a calculator ; s = 37.525
The confidence interval :
C.I = xbar ± [Tcritical * s/√n]
Tcritical(0.10 ; df = n - 1 = 9 - 1 = 8)
Tcritical at 90% = 1.860
C. I = 1262.11 ± [1.860 * 37.525/√9]
C.I = 1262.11 ± 23.266
(1238.845 ;1285.376)
± 23.266
The margin of error :
[Tcritical * s/√n]
[1.860 * 37.525/√9]
C.I = ± 23.266
Anything with || around it is a whole value. It’s always a positive. For example, |-56|=56. Now, if the negative was on the outside, it would be a negative like so; -|10| =-10