You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Answer and Step-by-step explanation:
Workings and solutions to a, b, & c can be viewed in the snapshot below:
Answer:
x(2x-17)
Step-by-step explanation:
2x^2 -11x-6x
2x^2-17x
x is common
x(2x-17)