Help please on linear math
2 answers:
Answer:
<h2>Option D is the correct option.
Step-by-step explanation:
Given that
9x - 8y = 0
finding y-intercept
put x = 0 , we get
9(0) - 8y + 5 = 0
Calculate the product
-8y + 5 = 0
Move the constant to L.H.S and change its sign
-8y = 0 - 5
Calculate the difference
-8y = -5
divide both sides of the equation by -8
-8y/-8 = -5/-8
Calculate
y = 5/8
Hope this helps...
Good luck on your assignment...
You might be interested in
Answer:
Step-by-step explanation:
This equation is more intimidating than the problem you have to solve.
You know that the sine of everything is always between -1 and +1. So for the entire expression to be >= 0, the a*tan(pi/8) bit has to be 1 at least. Given this, we can forget about the sin(...) term of the equation for the remainder of solving it.
You already figured out that tan(pi/8) is sqrt(2)-1.
So what we're saying is a * (sqrt(2) - 1) has to be 1 at least.
If we solve a(sqrt(2)-1) >= 1 for a we get:
a = 1/(sqrt(2)-1)