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2 years ago

I need help with this please i can't figure out.

Mathematics

2 answers:

Gala2k [10]2 years ago

6 0

That should be right, because the absolute value of -9 would be 9, but the negative sign in front makes it -9.

shepuryov [24]2 years ago

6 0

Your selected answer is correct because the absolute value of -9 is 9, and the negative sign outside the absolute number symbols makes it 9 negative, so -9=-9. BUT, we notice that there are choices for "greater than or equal to" and "less than or equal to". Those ones are correct too because it can be one or the other (greater than or equal to, less than or equal to).

Equal to, less than or equal to, greater than or equal to (Choices 3, 4, and 5)

:)

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What is the value of X?

Leviafan [203]

Answer:

w = 31

Step-by-step explanation:

To find the value of w:

We know that the three angles in a triangle add to 180 degrees

w + w + (4w-6) =180

Add like terms

6w-6 = 180

Add 6 to each side

6w -6+6 =180+6

6w = 186

Divide each side by 6

6w/6 = 186/6

w = 31

7 0

2 years ago

PLEASE HELP will give 99 points.

Yuri [45]

The answer is 90 + 45 because BOC is a right angled triangle where angle BOC is 90 and angle BOK is 45 because 90 ÷2. A OK Is a right angled triangle so angle AOB is 90 as well so to find angle AOK we plus 90 and 45 which is 135 degrees.

8 0

2 years ago

Read 2 more answers

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$