3 years ago

How do. You solve {4+3[2^3÷2

Mathematics

1 answer:

IgorC [24]3 years ago

7 0

Answer:

Step-by-step explanation:

Simplify the following:

4 + 3×2^3/2

3×2^3/2 = (3×2^3)/2:

4 + (3×2^3)/2

Combine powers. (3×2^3)/2 = 3×2^(3 - 1):

4 + 3×2^(3 - 1)

3 - 1 = 2:

4 + 3×2^2

2^2 = 4:

4 + 3×4

3×4 = 12:

4 + 12

4 + 12 = 16:

Answer: 16

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