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3 years ago

0+47=47 is what property

Mathematics

2 answers:

Ivanshal [37]3 years ago

4 0

Additive identity property

lys-0071 [83]3 years ago

4 0

Additive identity property $\\$

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Please explain how to do this one as well ...

kirza4 [7]

Answer:

x = 13

Step-by-step explanation:

Step 1: Define

f(x) = (x - 1)/2

f(x) = 6

Step 2: Substitute and solve for x

6 = (x - 1)/2

12 = x - 1

x = 13

4 0

3 years ago

A sequence can be generated by using an = an-1 + 4, where a1 = 6 and n is a whole number greater than 1. What are the first four

Firlakuza [10]

Answer:

The first four terms are 4,8,12,16

Step-by-Step Explanation:

The given relation between the nth term and it's previous term is given by:

$\boxed{an = an - 1 + 4}$

GiveN:

a1 = 4

Now finding the other three terms of the AP with the given relation.

$a2 = a1 + 4$

Putting a1 = 4,

$a2 = 4 + 4 = 8$

Now, Third term:

$a3 = a2 + 4$

Putting a2 = 8,

$a3 = 8 + 4 = 12$

Now, Fourth term:

$a4 = a3 + 4$

Putting a3 = 12,

$a4 = 12 + 4 = 16$

Hence, The first four terms of the AP is 4, 8, 12 & 16.

7 0

2 years ago

What is the answer to this question

almond37 [142]

Answer:

C. 24 1/4

Step-by-step explanation:

You turn both the lowest and the highest values into improper fractions and subtract the numerators then turn it back into a mixed fraction.

7 0

2 years ago

Suppose lines EF and GH are reflected over the line Y equals X to form the lines JK and LM which statement would be true about t

katrin [286]

Answer:

A) JK and LM will be parallel to each other.

Step-by-step explanation:

On reflection on $y=x$ line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate

$(x,y)\rightarrow (y,x)$

Points on line EF

$(0,6) , (-5,-2)$

On reflection of this line on $y=x$ the new points we get for line JK are

$(6,0),(-2,-5)$

Points on line GH

$(-4,9),(-9,1)$

On reflection on y=x line the new points we get for line LM are

$(9,-4),(1,-9)$

Slope of line JK

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-5)-0}{(-2)-6} \\m=\frac{-5}{-8}=\frac{5}{8}$

Slope of line LM

$m=\frac{y_2-y_1}{x2-x1}\\m=\frac{(-9)-(-4)}{1-9} \\m=\frac{-9+4}{-8}=\frac{-5}{-8}\\m=\frac{5}{8}$

For two line to be parallel, their slopes will be same.

$m_{JK} =\frac{5}{8} , m_{LM}=\frac{5}{8}$

Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.

5 0

3 years ago

Calculate 36%of $4500

Aleksandr [31]

Answer:

1620

Step-by-step explanation:

0.36*4500=1620

7 0

3 years ago

Read 2 more answers