Ask question

Ask question

All categories

3 years ago

7

The value of x is . I cant find any answers on this

2 answers:

GenaCL600 [577]3 years ago

5 0

The angle that is next to 9x should be 180 - 9x because it is a straight angle.

Since there are 180 degrees in an angle we can add up the values to 180 and solve for x.

180- 9x + 5x + 9 + x = 180
-3x = -9
x = 3

Hope this helped!

UkoKoshka [18]3 years ago

4 0

First, we should find the third angle in that triangle. Since the angles form a straight line, we know they are supplementary (adding up to 180°). Let's set it up like this:

9x + R = 180
R = 180 - 9x

Now we have the value of angle R, the third angle in the triangle. Since all angles in a triangle add up to 180°, we can set it up like this:

R + S + T = 180
180 - 9x + 9 + x + 5x = 180
189 - 3x = 180
-3x = -9
x = 3

The value of x is 3°.

You might be interested in

Dante is selling donuts outside a huge office building every morning. The first week

inysia [295]

Answer:

<h2>$205</h2>

Step-by-step explanation:

45 - 25 = 20

65 - 45 = 20

as you can see the common difference between the 3 consecutive numbers 25 , 45 and 65 is a constant (20)

so ,we are in an arithmetic sequence case with :

first term 25

common difference r = 20

Let’s label the sequence: Un

then

Un = U1 + (n-1)×r

= 25 + (n-1)×20

= 20n + 5

for n = 10 → U10 = 20(10) + 5 = 200 + 5 = 205

5 0

3 years ago

What are the solutions of 5x+23>2x−4?

zhuklara [117]

Answer:

answer :

$x > - 9$

solution:

step 1 :

$5x - 2x > - 4 - 23$

step 2 :

$3x > - 27$

step 3 :

$x > \frac{ - 27}{3}$

final step :

$x > - 9$

4 0

3 years ago

At the city museum, child admission is

natita [175]

101 child tickets were sold that day

6 0

3 years ago

Evaluate the integral Integral from 0 to 1 Integral from 0 to 3 Integral from 3 y to 9 StartFraction 6 cosine (x squared )Over 5

Natalka [10]

Answer:

$\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz$ $=\frac{18}{5}(1+\frac{sin2}{2})$

Step-by-step explanation:

cosine x²= cos x²

Rule

$\int x^ndx= \frac{x^{n+1}}{n+1}+c$

$\int cos \ mx \ dx = \frac{sin \ mx}{m}+c$
$\int \frac{1}{\sqrt x}dx = \frac{\sqrt x}{\frac{1}{2}} +c= 2\sqrt x+c$

Given that,

$\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz$

$=\int ^1_0[\int^3_0(\int^9_{3y} \frac{6cos x^2}{5\sqrt z}dz)dy]dz$

$=\int^1_0[\int^3_0([\frac{6cos x^2 \times \sqrt z}{5\times \frac{1}{2}}]^9_{3y})dy]dx$

$=\int^1_0[\int^3_0([\frac{12cos x^2 \times( \sqrt 9-\sqrt{3y})}{5}])dy]dx$

$=\int^1_0[\int^3_0([\frac{12cos x^2 \times( 3-\sqrt{3y})}{5}])dy]dx$

$=\int^1_0[\frac{12cos x^2 \times( 3y-\frac{\sqrt{3}y^\frac{3}{2}}{\frac{3}{2}})}{5}]^3_0dx$

$=\int^1_0[\frac{12cos x^2 \times( 3.3-\frac{2\sqrt{3}.3^\frac{3}{2}}{3})}{5}]^3_0dx$

$=\int^1_0[\frac{12cos x^2 \times( 9-6)}{5}]dx$

$=\frac{18}{5}\int^1_02cos x^2dx$

$=\frac{18}{5}\int^1_0(1+cos2x)dx$

$=\frac{18}{5}[(x+\frac{sin2x}{2})]^1_0$

$=\frac{18}{5}(1+\frac{sin2}{2})$

6 0

3 years ago

PLEASE HELP FOR BRAINLIEST

Schach [20]

Answer:

b=74 degrees c=1O6 degrees

Step-by-step explanation:

B is 74 because its across from the 74 degrees

C is 1O6 degrees because 18Odegrees-74degrees-1O6degress

5 0

2 years ago

Read 2 more answers