Each train carried 64141 kg of flour and each truck carried 9163 kg of flour.
Step-by-step explanation:
Let the no. of kg of flour carried by each train be 'a'
Let the no. of kg of flour carried by each truck be 'b'
Total flour = 403172 kg
No. Of trains = 5
No. of trucks = 9
a = 7(b)
5a + 9b = 403172
5(7b) + 9b = 403172
35b + 9b = 403172
44b = 403172
b = 403172/44
b = 9163
Each truck carried 9163 kg of flour.
a = 7b
a = 7(9163)
a = 64141
Each train carried 64141 kg of flour.
That’s a very good question but i don’t know the answer however it may be animals
Answer:
16 days
Step-by-step explanation:
Given that:
Number of paramecium Aurelia doubles every 1.25days
5 days ago ; number of paramecium Aurelia = 1
How many are there now?
Using the relation :
Multiplier^(total number of days / time it takes to multiply)
Multiplier = doubles = 2
Total number rof days =. 5
Time it takes to. Multiply = 1.25
The formula becomes :
Number(n) of ptotozoan in 5days is given by 2^(5/1.25)
n = 2^(5/1.25)
n = 2^4
n = 2 * 2 * 2 * 2 =. 16
We know, Volume of a Cube = Edge³
so, it would be: f(v) = a³
Hope this helps!
√<span>108x^5y^6
First, break up </span><span>√108 :
</span>√108 = √4 x √27 = 2 x √3 x √9 = 2 x √3 x 3 = 6<span>√3
</span><span>Since the x^5 is under a root of 2, that means we can take out an x^2 and leave one x under the radical :
</span>√x^5 = x^2 (<span>√x)
</span><span>Since the y^6 is raised to an even power and the root is even (2), that means we can take out all of the y's without leaving any under the radical :
</span><span>√y^6 = y^3
</span><span>Now, combine all of our simplified forms into one expression:
6x^2y^3</span><span>√3x</span><span>
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