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3 years ago

What is the average speed of the zebra during the time between 0s and 40s

Mathematics

1 answer:

Len [333]3 years ago

7 0

You would have to know the rate that it is going at to solve it I think

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The area of a rectangle is 8x3 + 6x2 - 10x. The width of the rectangle is 2x. Find the length of the rectangle.

Sladkaya [172]

2x multiplies to all numbers:
2x x 8x3 = 16x4
2x x 6x2 = 12x3
2x x -10x = -20x2

Answer: 16x4 + 12x³ - 20x²

Hope this helps :)

4 0

3 years ago

What is a first step to isolate the variable ?btw it’s for iready lol

kirza4 [7]

Answer:

The first step would be to multiply 2x - 1 by 6, which would be 12x - 6 .

5 0

2 years ago

Read 2 more answers

Answer both parts a and b for full credit.

Maslowich

Answer:

A) The store charges $94.50 for the skis!

B) The final price is 150% of the original price!

Step-by-step explanation:

A) 63 x (1 + 0.50) = 94.5

B) 94.50 = P(63)

94.50 (1/63)=P(63)(1/63)

1.50

6 0

3 years ago

Mrs. Barnes cuts1/2 of a piece of construction paper. She uses 1/6

denpristay [2]

Answer:

Step-by-step explanation:

what fraction?? she uses 1/6 of the construction paper

if you are referring to how much paper is left, its 2/6 aka 1/3

4 0

2 years ago

Read 2 more answers

Calculate, to four decimal places, the first ten terms of the sequence. an = 1 +(−4/9)^n

Lemur [1.5K]

The first ten terms of the sequence $a_n=1 + (-\frac{4}{9} )^n$ is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

$a_n=1 + (-\frac{4}{9} )^n\\\\When\ n=1:a_1=1 + (-\frac{4}{9} )^1=0.5556\\\\When\ n=2:a_2=1 + (-\frac{4}{9} )^2=1.1975\\\\When\ n=3:a_3=1 + (-\frac{4}{9} )^3=0.9122\\\\When\ n=4:a_4=1 + (-\frac{4}{9} )^4=1.039\\\\When\ n=5:a_5=1 + (-\frac{4}{9} )^5=0.9827\\\\When\ n=6:a_6=1 + (-\frac{4}{9} )^6=1.0077\\\\When\ n=7:a_7=1 + (-\frac{4}{9} )^7=0.9966\\\\When\ n=8:a_8=1 + (-\frac{4}{9} )^8=1.0015\\\\When\ n=9:a_9=1 + (-\frac{4}{9} )^9=0.9993\\\\$

$When\ n=10:a_{10}=1 + (-\frac{4}{9} )^{10}=1.0003\\$

The first ten terms of the sequence $a_n=1 + (-\frac{4}{9} )^n$ is<em> 0.5556, 1.1975, 0.9122, 1.039, 0.9827, 1.0077, 0.9966, 1.0015, 0.9993 and 1.0003</em>

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0

2 years ago