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True [87]
3 years ago
8

What is the average speed of the zebra during the time between 0s and 40s

Mathematics
1 answer:
Len [333]3 years ago
7 0
You would have to know the rate that it is going at to solve it I think
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Tickets to Dundee crowns mr.dchs are $3 for students and $5 for adults. The number of adult tickets sold was 195 more than the n
Maurinko [17]

Answer: number of tickets sold to adult = 566

Step-by-step explanation:

Let x = number of tickets sold by DCHS to students.

Let y = number of tickets sold DCHS to adults.

Tickets to Dundee crowns mr.dchs are $3 for students and $5 for adults.

This means cost of total tickets sold to students and adults is $3x and $5y respectively.

If DCHS collected $3943 for the tickets, then we have

3x + 5y = 3943 - - - - - -1

The number of adult tickets sold was 195 more than the number of student tickets. This means

y = x +195.

Put y = x +195 in equation 1

3x + 5(x+195) = 3943

3x + 5x + 975= 3943

8x +975=3943

8x = 3943-975= 2968

x = 2968/8 = 371

y = 371 + 195= 566

4 0
3 years ago
What is the difference between 403,951 and 135,211
Simora [160]
403951-135211=
268740
7 0
3 years ago
Explain how to form a linear combination to eliminate the variable y for this system 2x-3y=3 5x+2y=17
Nadusha1986 [10]
 Well to be exact the answer is x=3 y=1
3 0
3 years ago
Read 2 more answers
NEED HELP ASAP!!! ALGEBRA 1 STUFF (20pts.)
3241004551 [841]
It's not actually 20 pts it's 10 pts if you send a question and you want 20 pts off it would be 10 for other ppl. like 

10pts off = 5
20pts off = 10
30pts off = 15

and so on so it's like counting by 5's each time you lose points

4 0
3 years ago
The electric-vehicle manufacturing company Tesla estimates that a driver who commutes miles per day in a Model S will require a
saul85 [17]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Please find the complete question in the attached file.

In this question, we assume that "x" denotes as  an actual time of the  battery charging, that is a uniform random variable that x \sim U(90, 120)

 In point a:

so, pdf of x =

\to f(x)= \frac{1}{120-90}  = \frac{1}{30} \\\\\to 90 < x

In point b:

To find

\to P(x

In point c:

\to P(x

In point d:

\to P(95< x< 110)

= \int^{110}_{95} \frac{1}{30} \ dx\\\\= \frac{110-95}{30} \\\\= \frac{15}{30} \\\\= \frac{1}{2}

6 0
3 years ago
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