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Archy [21]
3 years ago
5

FOR 12 POINTS I NEED HELP ASAP! Consider the system of linear equations. 5 x + 10 y = 15. 10 x + 3 y = 13 To use the linear comb

ination method and addition to eliminate the x-terms, by which number should the first equation be multiplied? –2 Negative one-half One-half 2
Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

Do you mean which equation should the 5x+10=15 be multiplied to?

it would be -2

Step-by-step explanation:

This is because 5 times -2 is -10

and so when you add the (now) x value of the first equation to the x value of the second equation, it gets 0

which makes it eliminated!

-10x+10x=0

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The graph shows two lines, A and B.
scoundrel [369]

Answer:

second option: (4, 4) is the solution to both lines A and B.

Step-by-step explanation:

You know that the equation of line A is:

y=-3x+15

and the equation of line B is:

y=\frac{1}{2}x+2

The point in which the line A intersects with the line B is the solution of the sytstem of equations.

You can observe in given graph that the point of intersection of Line A and Line B is: (4,4)

Therefore (4, 4) is the solution to both lines A and B.

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3 years ago
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Answer:

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2 years ago
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Simplify the following expression.<br><br> 6 - (-19)
NISA [10]

Answer:

The answer is 25 but I'm not sure you can simplify a whole number

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3 years ago
The area of another rectangle is x² + 5x + 6. If one side measures (x + 2), what is the measure of the other
tiny-mole [99]
  • L=x+2
  • We need B

\\ \sf\longmapsto LB=Area

\\ \sf\longmapsto B(x+2)=x^2+5x+6

\\ \sf\longmapsto B(x+2)=(x+2)(x+3)

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8 0
2 years ago
Use the normal distribution of SAT critical reading scores for which the mean is 502 and the standard deviation is 116. Assume t
PSYCHO15rus [73]

Answer:

(a) 93.19%

(b) 267.3

Step-by-step explanation:

The population mean and standard deviation are given as 502 and 116 respectively.

Consider, <em>X</em> be the random variable that shows the SAT critical reading score is normally distributed.

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P(X

Thus, the required percentage is 93.19%

(b)

The number of SAT verbal scores that are expected to be greater than 575 can be calculated as:

P(X>575)=P(\frac{x-502}{116}>\frac{575-502}{116}\\P(X>575)=P(Z>\frac{575-502}{116})\\P(X>575)=P(Z>0.6293)\\P(X>575)=0.2673

So,

Out of 1000 randomly selected SAT verbal scores, 1000(0.2673) = 267.3 are expected to have greater than 575.

8 0
3 years ago
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