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SIZIF [17.4K]
4 years ago
7

If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third. What are the i

ntegers?
Mathematics
1 answer:
Murljashka [212]4 years ago
6 0

Answer:

<h2>45, 46, 47</h2>

Step-by-step explanation:

n, n + 1, n + 2 - three consecutive integers

The equation:

138 - n = (n + 1) + (n + 2)

138 - n = n + 1 + n + 2                 <em>combile like terms</em>

138 - n = 2n + 3           <em>subtract 138 from both sides</em>

-n = 2n - 135               <em>subtract 2n from both sides</em>

-3n = -135            <em>divide both sides by (-3)</em>

n = 45

n + 1 = 46

n + 2 = 47

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svlad2 [7]

Let A unit be a; B unit be b

a + b = 95

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3a + 5(95 -a) = 395

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a + b = 95

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Therefore, a = 40; b = 55.

Hope this helps

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3 years ago
Can somebody help me?
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Solve the portion 20/3 = ?/6
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3 years ago
Point A is the point of concurrency of the angle bisectors of ΔDEF.
amm1812

The correct answer is option A which is ZA = 3 cm

<h3>What is the triangle?</h3>

Triangle is a shape made of three sides in a two-dimensional plane. the sum of the three angles is 180 degrees.

The triangle is shown below.

From the triangle, A is the concurrency point of angle bisectors of all vertices.

Consider ΔAYD,

Using the Pythagorean theorem,

AD² = AY² + YD²

5² = AY² + 4²

25 = AY² + 16

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AY² = 9

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Consider triangles ADY and ADZ.

∠AYD ≅∠AZD=90

∠ADY≅∠ADZ ( Angle bisector)

AD ≡ AD (common side)

The two triangles are congruent by the AAS postulate.

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