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SIZIF [17.4K]
3 years ago
7

If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third. What are the i

ntegers?
Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

<h2>45, 46, 47</h2>

Step-by-step explanation:

n, n + 1, n + 2 - three consecutive integers

The equation:

138 - n = (n + 1) + (n + 2)

138 - n = n + 1 + n + 2                 <em>combile like terms</em>

138 - n = 2n + 3           <em>subtract 138 from both sides</em>

-n = 2n - 135               <em>subtract 2n from both sides</em>

-3n = -135            <em>divide both sides by (-3)</em>

n = 45

n + 1 = 46

n + 2 = 47

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Answer:

the approximate area of this circle is 200.96 inches long.

Step-by-step explanation:

To answer this problem we need to remember that the area of a circle is given by the formula:

Area = πr^2 where r is the radius.

and the perimeter is:

Perimeter = 2πr

Now, the problem tells us that the circle is enclosed by a piece of rope that's 50.24 inches long. So the perimeter of the circle is 50.24 inches.

Since we have the value of the perimeter and the value of pi, we are going to substitute these values in the perimeter formula to find r.

Perimeter = 2πr

50.24=2(3.14)r

50.24= 6.28r

50.24/6.28= r

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Thus, the radius of the circle is 8 inches long.

Now, we can use this value to find the area of the circle:

Area = πr^2

Area = π8^2

Area = 3.14 (64)

Area = 200.96

Therefore, the approximate area of this circle is 200.96 inches long.

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What is the length of the cylinder's height? Please help​
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Answer:

  • Height = <u>9</u><u> </u>cm which means <u>Option </u><u>C </u>is the answer

Step-by-step explanation:

In the question we are given ,

  • Volume of cylinder = <u>2</u><u>2</u><u>5</u><u>π</u><u> </u><u>cm³</u>

  • Radius of cylinder = <u>5 cm</u>

And , we have to find the <u>height</u><u> of</u><u> </u><u>cylinder</u><u> </u>.

We know that ,

\longrightarrow \pink{ \boxed{Volume \:  of \:  Cylinder = \pi r {}^{2}h  }} \longleftarrow

Our solution starts from here :

\longmapsto \: \pi \: r {}^{2} h = 225\pi

<u>Step </u><u>1</u><u> </u><u>:</u> Cancelling π with π :

\longmapsto \:  \cancel{\pi} \: r {}^{2} h = 225 \cancel{\pi}

<u>Step </u><u>2</u><u> </u><u>:</u> Substituting value of radius which is 5 cm in the formula :

\longmapsto \: (5) {}^{2}  \times h = 225

\longmapsto \: 25h = 225

<u>Step </u><u>3 </u><u>:</u> Transposing 25 to right hand side :

\longmapsto \: h =  \frac{225}{25}

<u>Step </u><u>4</u><u> </u><u>:</u> Cancelling 225 by 25 :

\longmapsto \:   \red{\boxed{h = 9 \: cm}}

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<h2 /><h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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A circle has a circumference of 9π what is the diameter?
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C=πd  where C=circumference, π=the constant pi, and d=diamter

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