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iren2701 [21]
3 years ago
10

SOMEONE HELP!

Mathematics
1 answer:
enyata [817]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

12

Since the denominators are like, add the numerators leaving the denominator

= \frac{x+4+x-1}{x-2}

= \frac{2x+3}{x-2}

15

We require the denominators to be like before we can add.

factor x² - 4 as a difference of squares

x² - 4 = (x + 2)(x - 2)

Expressing as

\frac{x^2-6x}{x+2} + \frac{2x-12}{(x+2)(x-2)}

multiply the numerator/denominator of the first fraction by (x - 2)

= \frac{(x-2)(x^2-6x)}{(x+2)(x-2)} + \frac{2x-12}{(x+2)(x-2)}

Expand and simplify the numerators, leaving the denominator

= \frac{x^3-6x^2-2x^2+12x+2x-12}{(x+2)(x-2)}

= \frac{x^3-8x^2+14x-12}{(x+2)(x-2)}


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Step-by-step explanation:

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