Answer:
10
Step-by-step explanation:
We start by getting the value of x
We have this as follows:
5x ≤ 43 + 11
5x ≤ 54
x ≤ 54/5
x ≤ 10.8
As we can see, the maximum integer closest to this decimal is the value 10
If you mean
3 times square root of 125 then go to AAA
if you mean ∛125 then go to BBBB
AAAAAA
3 times √125=3 times 5√5=15√5
BBBBBBB
∛125=5 or -5
To solve for the length of a perimeter, use
L = P/2﹣w
L = 66/2 - 7
L = 33 - 7
L = 26
The length is 26
Answer:
<em>E. have the same experiences as the treament group, except for</em><em> </em><em>re</em><em>ceiving the treament variable.</em>
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
