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4 years ago

PlZ I WILL GVIE YUO 100 pointd

Mathematics

2 answers:

algol [13]4 years ago

7 0

Answer:

Domino's

Step-by-step explanation:

What you need to do is first times $9 by 20 because she bought 20 pizzas to get $180.

Next you will add the cost of the delivery which is $4.50 to get $184.50.

You will then take the tax which is 5% and times it by $184.50 to get $9.23.

You will add the $9.23 to $184.50 to get $193.73 for Domino's.

For Pizza Hut, you will times $11.50 and 20 to get $230 and that is already over Domino's price so Domino's is the better deal.

Luba_88 [7]4 years ago

3 0

Answer:

The right side Domino's

Step-by-step explanation:

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Answer:

A=πr^2

Step-by-step explanation:

A=πr^2

You have to multiply the radius * pi then square your answer

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4 years ago

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60% of students at a local high school participate in club activities. Rewrite this percent as a fraction

Setler79 [48]

Answer:

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Step-by-step explanation:

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3 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

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3 years ago

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romanna [79]

Answer:

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3 years ago

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babymother [125]

Answer:

Step-by-step explanation:

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