No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
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Answer:
A total of 387 centimeters of ribbon are used.
Step-by-step explanation:
We already know that two out of three pieces of ribbon are 1.25 meters.
The third piece of ribbon is 120 millimeters (mm) longer.
1 millimeters = 0.001 meters
120 x 0.001 = 0.12
That means that the third piece of ribbon is 0.12 meters longer than the first two. The length of the third ribbon is 1.25 m + 0.12 m = 1.37 m
In order to find the total number of meters of ribbon used, we need to do addition.
1.25 m + 1.25 m + 1.37 m = 3.87 m
But, the question is asking us the number of centimeters of ribbon that are used.
1 m = 100 cm
3.87 x 100 = 387 cm
Therefore, a total of 387 centimeters of ribbon are used.
Hope this helps! Have a blessed day! :)
Answer:
Musah's final point from the centre = 60.355 steps
Step-by-step explanation:
From the given information:
Musah stands at the centre of a rectangular field. He first takes 50 steps north, then 25 steps west and finally 50 steps on a bearing of 315°
The sketch for this information can be seen in the attached file below.
How far west is Musah's final point from the centre?
In order to determine how far west is Musah's,
Let d be the distance of how far;
Then d = QR + RS cos θ
In the North West direction,
cos θ = cos 45°
d = 25 + 50( cos 45°)
d = 25 + 50( 
)
d = 25 + 50( 0.7071)
d =25 + 35.355
d = 60.355 steps
Musah's final point from the centre = 60.355 steps
No, JN is not paralle to KM
Answer:
414
Step-by-step explanation:
substitute the given value 21 for x. so y=750-16(21)
y=750-336
y=414
