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8_murik_8 [283]
3 years ago
14

Which equation describes the line which passes through the points (0. 17, 0) and (0, 0.51)

Mathematics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

The equation of line which passes through the points (0. 17, 0) and (0, 0.51) is y=-3x+0.51.

Step-by-step explanation:

It is given that the line passing through the points (0. 17, 0) and (0, 0.51).

The slope of the line is

m=\frac{y_2-y_1}{x_2-x_1}=\frac{0.51-0}{0-0.17}=-3

The slope intercept form of the line is

y=mx+b

Where, m is slope and b is y-intercept.

Equation of the line is

y=-3x+0.51

The other way to write the equation is shown below.

The point slope form of the line is

y-y_1=m(x-x_1)

y-0=-3(x-0.17)                  ....(1)

y-0.51=-3(x-0)                 .....(2)

Therefore equation of line which passes through the points (0. 17, 0) and (0, 0.51) is y=-3x+0.51.

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<u>Answer</u>

0


<u>Explanation</u>

(2m)/(2m+3)-(2m)/(2m-3)=1

Simplifying the left hand first

(2m)/(2m+3)-(2m)/(2m-3) = {2m(2m-3) - 2m(2m+3)}/(4m²-9)

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So we can say that the equation has NO extraneous solutions.

Answer = 0

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