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dybincka [34]
2 years ago
9

Use the interactive to make a line that passes through the points 3'2 and -1'-1 slope

Mathematics
1 answer:
Oliga [24]2 years ago
7 0

The required equation of the line passing the coordinates will be y = 3/4x - 1/4

<h3 /><h3>Equation of a line</h3>

The standard equation of a line is expressed as y= mx + b

where

m is the slope

b is the y-intercept

Given the coordinate points on a line (3, 2) and (-1, -1)

Slope = -1-2/-1-3

Slope = 3/4

Determine the y-intercept

2 = 3/4(3) + b
2 = 9/4 + b

b = 2 - 9/4

b = -1/4

The required equation of the line passing the coordinates will be y = 3/4x - 1/4

Learn more on equation of a line here: brainly.com/question/18831322

#SPJ1

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PLEASE HELP! 40 POINTS
Vedmedyk [2.9K]

I'd start with setting up the equations. Calling x the number of students in most popular country 1, and y in country 2.

x + y = 44740

x - y = 5672

now solve for x1 and x2. You can subtract second from first:

0 + 2y = 39068

y = 19534

so

x = 5672 + 19534 = 25206

Add a sentence to answer it in words.

7 0
3 years ago
Read 2 more answers
How much money has to be invested at 5.9% interest compounded continuously to have $15,000 after 12 years?
scoray [572]

The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.

Step-by-step explanation:

The given is,

                Future value, F  = $15,000

                           Interest, i = 5.9%

              ( compounded continuously )

                            Period, t = 12 years

Step:1

           Formula to calculate the present with compounded continuously,

                                       F=Pe^{(i)(t)}...............(1)

           Substitute the values in equation (1) to find the P value,

                                  15000=Pe^{(0.059)(12)}          ( ∵ i = \frac{5.9}{100}=0.059 )

                                  15000=Pe^{0.708}

                                  15000=P(2.0299)             ( ∵ e^{o.708} =2.0299 )

            We change the P (Present value) into the left side,

                                        P=\frac{15000}{2.0299}

                                            =7389.427

                                            ≅ 7389.43

                                         P = $ 7389.43

Result:

           The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.  

                       

8 0
3 years ago
In the given triangle ABC, find DE. answers: 20 5 10 2.5
adell [148]

Answer:

5

Step-by-step explanation:

Let's call the length AD y.

\dfrac{x+2}{y}=\dfrac{8x-14}{2y} \\\\\\2(x+2)=8x-14 \\\\\\2x+4=8x-14 \\\\\\4=6x-14 \\\\\\6x=18 \\\\\\x=3 \\\\\\DE=x+2=3+2=5

Hope this helps!

5 0
3 years ago
Joan Messineo borrowed ​$47,000 at a 5​% annual rate of interest to be repaid over 3 years. The loan is amortized into three​ eq
tester [92]

Answer:

a) The value of the Annual Payment is A=$17,258.80

b) Is the picture in the attachment file

c) As you can see it in the picture with each payment, balance comes down, due it is the interest base, Interest portion comes down too.

Step-by-step explanation:

Hi

a) First of all, we are going to list the Knowns: VP=47000, i=5% and n=3, Then we can use A=\frac{VP}{\frac{1-(1+i)^{-n} }{i} } =\frac{47000}{\frac{1-(1+0.05)^{-3} }{0.03} }=17258.80. So this is the value of the Annual Payment

6 0
3 years ago
Please help me asap!!
Sauron [17]
I believe the answer is C
7 0
3 years ago
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