Find the product. <br> d j

From an airplane at an altitude of 1200m the angle of depression to a rock on the ground measures 28. Find the distance from the

nasty-shy [4]

Given that the plane is at altitude of 1200m and the angle of depression is 28°, to calculate the distance between the the plane and the rock we assume that we a have right triangle whereby the distance of the plane form the ground is the height, the distance from plane to the rock is the hypotenuse and the remaining distance is the base:
thus

sin θ=opposite/hypotenuse
θ=28°
opposite=1200m
hypotenuse=h
thus
sin 28=1200/h
h=1200/sin 28
h=2556.065 m

6 0

4 years ago

Which graph is the graph of this function?<br> 1-1-1 iſ r >6

Snowcat [4.5K]

Answer: welpies

Step-by-step explanation:

I need points so no help.

5 0

3 years ago

The breaking strength of a rivet has a mean value of 10,000 psi and a standard deviation of 500 psi. (a) What is the probability

velikii [3]

Answer:

a) 89.05% probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200

b) No, because one of the requirements of the central limit theorem is a sample size of at least 30.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$