The question is not well formatted. However, I have taken some educated guesses as to what it should be.
Since it requires the number of zeros in a product, one of them should be a multiple of 5 and the other an even number. Both numbers appear as odd numbers, so I believe the first number is while the other is either or .
Answer:
The product has 7 zeros
Step-by-step explanation:
The number of zeros is determined by the number of 10 in the factors. Now 10 = 2× 5. Hence, it is determined by the least number of factors of both 2 and 5.
45 = 5 × 9
Hence has 7 factors of 5.
Here, this has 15 factors of 2.
If we take the second number to be , then
.
The number of the factors of 10 in the product is the minimum of the number of factors of 2 and 5. Here, it is 7.
To fill in the blanks in the question:
When this number is written in ordinary decimal form, each 0 at its end comes from a factor of 10, or one factor of 2 and one factor of 5. Since there are 15 or 255 (make a choice, depending on the correct question) factors of 2 and 7 factors of 5, there are exactly 7 factors of 10 in the number. This implies that the number ends with 7 (seven) zeroes.