Answer:
Distance between two points= √(x2-x1)²+(y2-y1)²
D= 15units
Let "k" be the y-coordinate of A
A(-6,k)
B(3,2)
15= √(3--6)²+(2-k)²
Taking square of both sides to eliminate the square root.
15²=(9)²+(2-k)²
225=81+4-4k+k²
k²-4k - 140=0
Using Quadratic Formula to evaluate
k= 14 or k=-10
The Possible coordinates of A are
(-6,14) or (-6,-10)
(f+g)(x)=f(x)+g(x)=(2x-6)+(4x+7)=6x+1
(f-g)(x)=f(x)-g(x)=(2x-6)-(4x+7)=-2x-13
(fg)(x)=f(x)×g(x)=(2x-6)(4x+7)=8x^2-10x-42
(f+g)(-2)=f(-2)+g(-2)=(2(-2)-6)+(4(-2)+7)=-11
The answer for the following is B
Answer:
v = 2744 m³
Step-by-step explanation:
Volume of cube
= length³
= l³
= 14³
= 2744 m³
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Answer:
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