(x-4)/(3)(x+5)(x-5)
In order for the rational expression to be undefined, the denominator must be equal to 0.
Thus, set 3(x+5)9(x-5)=0
x=5 and -5
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Solve for </u><em><u>x</u></em>
- Cross-multiply:

- Distribute:

- Isolate <em>x</em> terms:

- Isolate <em>x</em> term:

- Isolate <em>x</em>:

- Rewrite:

9y - 5x = 20
or, (9y - 5x) / 20 = 1
or, 9/20 y - 1/4 x = 1
compare with x/a + y/b = 1
you'll get
x intercept (a) = -4
y intercept (b) = 20/9
When you evaluate the function f (x) = 4 • 7 ^ x for x = -1 you get:
f (-1) = 4 * 7 ^ -1
f(-1) = 4* 1/7
f (-1) = 0.5714
The next part of the question is not clear. If it refers to the function at x = 2 then:
f (2) = 4 * 7 ^ (2)
f(2) =4*49
f (2) = 196
If it refers to it in x ^ 2
f (x ^ 2) = 4 * 7 ^ (x ^ 2)