Answer:
20 team members
Step-by-step explanation:
5 liters is 5000 milliliters, so you divide 5000 by 250, and you get 20.
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
Learn more about probability at brainly.com/question/24756209
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Answer:
From the information provided we have:
PD ≅ RD (= 11)
∠CPD ≅ ∠CRD (= 90°)
They both have CD as the hypotenuse.
=> ΔCPD ≅ ΔCRD
=> ∠PCD ≅ ∠RCD
Now we know that:
∠RCP = ∠PCD + ∠RCD
∠RCP = 2 · ∠RCD
∠RCP = 2 · 33° = 66°
So the answer is B
Answer:
this is the answer
Step-by-step explanation:
