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2 years ago

PLEASE HELP ME PLEASE I NEED THE ANSWER AS FAST AS POSSIBLE PLEASE HELP PLEASE

Mathematics

1 answer:

Harman [31]2 years ago

8 0

It is 121 x 10^12 so the answer is A.

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I WILL MARK BRAINLIEST

N76 [4]

Answer:

y=70x+260

y=82x

Step-by-step explanation:

3 0

3 years ago

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Find the generating function for the sequence 1,-2,4,-8, 16, ...

kirill [66]

Answer:

$a(x)=\dfrac{1}{1+2x}$

Step-by-step explanation:

The generating function a(x) produces a power series ...

$a(x)=a_0+a_1x+a_2x^2+a_3x^3+\dots$

where the coefficients are the elements of the given sequence.

We observe that the given sequence has the recurrence relation ...

$a_0=1;a_n=-2a_{n-1} \quad\text{for n $>$ 0}$

This can be rearranged to ...

$a_n+2a_{n-1}=0$

We can formulate this in terms of a(x) as follows, then solve for a(x).

$\sum\limits^{\infty}_{n=1} {a_{n}x^n} =a(x)-a_0 \quad\text{and}\\\\\sum\limits^{\infty}_{n=1} {2a_{n-1}x^n} =(2x)a(x) \quad\text{so}\\\\\sum\limits^{\infty}_{n=1} {(a_n+2a_{n-1})x^n}=0=a(x)-a_0+2xa(x)\\\\a(x)=\dfrac{a_0}{1+2x}=\dfrac{1}{1+2x}$

The generating function is ...

a(x) = 1/(1+2x)

3 0

2 years ago

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Rewrite the expression in the form x

Serga [27]

Answer:

See below (I hope this helps!)

Step-by-step explanation:

When dividing exponential terms of the same base, we can simply subtract the exponents, therefore:

$\frac{x^{6} }{x^{8} } = x^{(6-8)} = x^{-2}$

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3 years ago

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac

Serhud [2]

Answer:

Step-by-step explanation:

A) $(tanx-4)(9sin^2x-1)=0\\\\\\$

$9sin^2x-1=0\\\\sin^2x=\frac{1}{9} sinx=\frac{1}{3}$ or $sinx=\frac{-1}{3}$

OR $tanx=4\\$

$3sin2x=3.2.sinx.cosx\\\\6.sinx.cosx-4.sinx= 2sinx.(3cosx-2)=0\\\\3.cosx=2 cosx=\frac{2}{3}$

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2 years ago

A circle is centered at (11, −9) and has a radius of 12.

ahrayia [7]

$\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllcl}
center\quad (&h,&\quad k)\qquad
radius=&r\\
&11&-9&12
\end{array}$

6 0

3 years ago