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3 years ago

PLEASE HELP ME PLEASE I NEED THE ANSWER AS FAST AS POSSIBLE PLEASE HELP PLEASE

Mathematics

1 answer:

Harman [31]3 years ago

8 0

It is 121 x 10^12 so the answer is A.

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Write a real world problem that can be solved using the equation, 5x = 3x + 20

Natali5045456 [20]

-3x from both sides so it looks like 2x=20 and divide by 2 and x=10

8 0

3 years ago

A flower shop acquired 80 new customers last year. Costs in the marketing and sales areas were the following:

icang [17]

Using proportions, it is found that the Customer Acquisition Cost was of $1,215.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount.

In this problem, the customer acquisition cost is the spending in sales divided by the number of customers added.

80 customers were added, considering costs of 1200 + 9000 + 87000 = $97,200, hence:

97200/80 = $1,215.

More can be learned about proportions at brainly.com/question/24372153

5 0

2 years ago

Which of the following functions are homomorphisms?

Vikentia [17]

Part A:

Given $f:Z \rightarrow Z,$ defined by $f(x)=-x$

$f(x+y)=-(x+y)=-x-y \\ \\ f(x)+f(y)=-x+(-y)=-x-y$

but

$f(xy)=-xy \\ \\ f(x)\cdot f(y)=-x\cdot-y=xy$

Since, f(xy) ≠ f(x)f(y)

Therefore, the function is not a homomorphism.

Part B:

Given $f:Z_2 \rightarrow Z_2,$ defined by $f(x)=-x$

Note that in $Z_2$ , -1 = 1 and f(0) = 0 and f(1) = -1 = 1, so we can also use the formular $f(x)=x$

$f(x+y)=x+y \\ \\ f(x)+f(y)=x+y$

and

$f(xy)=xy \\ \\ f(x)\cdot f(y)=xy$

Therefore, the function is a homomorphism.

Part C:

Given $g:Q\rightarrow Q$ , defined by $g(x)= \frac{1}{x^2+1}$

$g(x+y)= \frac{1}{(x+y)^2+1} = \frac{1}{x^2+2xy+y^2+1} \\ \\ g(x)+g(y)= \frac{1}{x^2+1} + \frac{1}{y^2+1} = \frac{y^2+1+x^2+1}{(x^2+1)(y^2+1)} = \frac{x^2+y^2+2}{x^2y^2+x^2+y^2+1}$

Since, f(x+y) ≠ f(x) + f(y), therefore, the function is not a homomorphism.

Part D:

Given $h:R\rightarrow M(R)$ , defined by $h(a)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)$

$h(a+b)= \left(\begin{array}{cc}-(a+b)&0\\a+b&0\end{array}\right)= \left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right) \\ \\ h(a)+h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)+ \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)=\left(\begin{array}{cc}-a-b&0\\a+b&0\end{array}\right)$

but

$h(ab)= \left(\begin{array}{cc}-ab&0\\ab&0\end{array}\right) \\ \\ h(a)\cdot h(b)= \left(\begin{array}{cc}-a&0\\a&0\end{array}\right)\cdot \left(\begin{array}{cc}-b&0\\b&0\end{array}\right)= \left(\begin{array}{cc}ab&0\\-ab&0\end{array}\right)$

Since, h(ab) ≠ h(a)h(b), therefore, the funtion is not a homomorphism.

Part E:

Given $f:Z_{12}\rightarrow Z_4$ , defined by $\left([x_{12}]\right)=[x_4]$ , where $[u_n]$ denotes the lass of the integer $u$ in $Z_n$ .

Then, for any $[a_{12}],[b_{12}]\in Z_{12}$ , we have

$f\left([a_{12}]+[b_{12}]\right)=f\left([a+b]_{12}\right) \\ \\ =[a+b]_4=[a]_4+[b]_4=f\left([a]_{12}\right)+f\left([b]_{12}\right)$

and

$f\left([a_{12}][b_{12}]\right)=f\left([ab]_{12}\right) \\ \\ =[ab]_4=[a]_4[b]_4=f\left([a]_{12}\right)f\left([b]_{12}\right)$

Therefore, the function is a homomorphism.

7 0

3 years ago

The population of a city is 250,000 and the annual growth rate is 2.2%. Write an equation to model the population y after x year

Zinaida [17]

Answer:

$y= 250000(1.022)^x$

Step-by-step explanation:

The population of a city is 250,000 and the annual growth rate is 2.2%

General equation for exponential growth is

$y= P(1+r)^x$

Where y is final population and P is the initial population

'r' is the rate of growth and x is the number of years

p = 25000 and r= 2.2%= 0.022. Replace all the values in the general equaiton

$y= P(1+r)^x$

$y= 250000(1.022)^x$

3 0

3 years ago

There are 15 m and ms that are peanut or small, 2 m and ms that are peanut and small, and 9 m and ms that are small. How many m

GarryVolchara [31]

Answer:

4m and ms are peanut

Step-by-step explanation:

9+2=11 and theres 15 total so 15-11= 4

3 0

3 years ago