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slega [8]
3 years ago
12

Can someone help me with these? I need some help.

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

1) \sqrt{569}  2) 8   3) 0.8  4) \sqrt[10]{61}

Step-by-step explanation:

The equation for pythagoream theorem is

a^2 + b^2 = c^2  (the caret "^" represents exponents)

A = a side length

B = another side length

C = the hypotnuse which is the slanted side of the right triangle.

To solve these problems plug in the known values into the equation then solve.

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One card is drawn from a well shuffled deck of 52 cards find the probability of getting a red 10
Julli [10]
The probability of getting a red card is 1/2 and the probability of getting a 10 is 4/52. To find the probability of getting both a red card and a 10, multiply the two.

(1/2)(4/52) = 4/104
4/104 = 1/26

Therefore, the probability is 1/26
7 0
3 years ago
Which equation has the steepest graph
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I know it is between b and c i am not sure cause they are both similar in the way they look but if i had to choose maybe B 
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Read 2 more answers
PLEASE HELP ME FIGURE OUT WHICH ONE I GOT WRONG, TYSMM :)
otez555 [7]

Answer:

da one in the middle and i do relize this is a test becuse i just took it.

Step-by-step explanation:

6 0
3 years ago
6.4×10³+5.2×10³<br>how to solve this?​
zheka24 [161]

Answer: 11,600

Step-by-step explanation: 10³ = 10 x 10 x 10 = 1,000.

1,000 x 6.4 = 6,400.

1,000 x 5.2 = 5,200.

6,400 + 5,200 = 11,600

3 0
3 years ago
Stock A ‘s returns have a standard deviation of 0.5, and stock B’s returns have standard deviation of 0.6.The correlation coeffi
galben [10]

Answer:

The variance of the profile is 0.2179.

Step-by-step explanation:

We are given the following in the question:

\sigma_A = 0.5\\\sigma_B = 0.6\\\rho_{A,B} = 0.5\\w_A = 70\% = 0.7\\w_B = 30\% = 0.3

Variance of portfolio is given by:

w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}

Cov_{A,B} = \rho_{A,B} \times \sigma_A \times \sigma_B \\=0.5\times 0.5 \times 0.6\\=0.15

Putting values, we get,

w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}\\=(0.7)^2(0.5)^2 + (.3)^2(0.6)^2 + 2(0.7)(0.3)(0.15)\\=0.2179

Thus, the variance of the profile is 0.2179.

4 0
3 years ago
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