The answer is 5a. 3a- 4a is -1 then you add -1 and 6, and your outcome comes out to be 5a.
x + y = 3
- x - x
y = -x + 3
y - y₁ = m(x - x₁)
y - (-1) = -1[x - (-1)]
y + 1 = -1(x + 1)
y + 1 = -1(x) - 1(1)
y + 1 = -x - 1
- 1 - 1
y = -x - 2
The answer is B.
The given operation involves just swapping the two rows, so carrying out
on the matrix gives
![\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D5%265%265%5C%5C1%26-%5Cdfrac23%265%5Cend%7Barray%7D%5Cright%5D%5Cto%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26-%5Cdfrac23%265%5C%5C5%265%265%5Cend%7Barray%7D%5Cright%5D)
Answer:
15 4/4
Step-by-step explanation:
Hi there,
x(x + 19) = -34
I'm going to solve your equation step-by-step.<span><span>x<span>(<span>x + 19</span>) </span></span>= <span>−34
</span></span>Step 1: Simplify both sides of the equation.<span><span><span>x2 </span>+ <span>19x </span></span>= <span>−34
</span></span>Step 2: Subtract -34 from both sides.<span><span><span><span>x2 </span>+ <span>19x </span></span>− <span>(<span>−34</span>) </span></span>= <span><span>−34 </span>− <span>(<span>−34</span>)
</span></span></span><span><span><span><span>x2 </span>+ <span>19x </span></span>+ 34 </span>= 0
</span>Step 3: Factor left side of equation.<span><span><span>(<span>x + 2</span>) </span><span>(<span>x + 17</span>) </span></span>= 0
</span>Step 4: Set factors equal to 0.<span><span><span>x + 2 </span>= <span><span><span>0<span> or </span></span>x </span>+ 17 </span></span>= 0
</span><span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−17
</span></span>Answer:<span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−<span>17
Hope this helps! :)</span></span></span>
