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Nikitich [7]
3 years ago
10

Mezcla de una señal con otra para facilitar su transporte o transmisión.

Computers and Technology
1 answer:
Brrunno [24]3 years ago
6 0

Answer:

telecomunicaciones

Explanation:

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A student is curious about how a Web site appears on his computer screen. On a piece of paper,
nata0808 [166]

A student is curious about how a Web site appears on his computer screen. There is a communication between the client and the server in the Application Layer.

Explanation:

  • When we choose to open a webpage (in any browser) the seventh layer of the OSI model - called Application layer will help to do that.
  • What happens after we write the webpage address in address bar is that the Application layer protocol (also called HTTP) formats and sends the request from the client's browser (Internet Explorer, Mozilla Firefox , Opera, Safari etc.) to the server.
  • It also formats and sends the server's respond back to client's browser. This process happens very fast and all the OSI model layers are processing in it (not only the Application layer).
  • All the layers are working together and each of them is responsible for some particular job, but all together they work as one. The layers communicate with each other and in case of error they will retry and fix the error or if they are unable to do it, the responsible layer will inform the user about the source of the problem.
  • What happens when page is requested and received? If we will remove the graphical and visual image and look at the process that computer does. We will see a set of commands, mathematical algorithms, symbols, letters and not understandable codes and processes.
  • When data is sent from "A" to "B", a transport layer is responsible to send and deliver it correctly and exactly the same, what was requested.
  • If the request, processed by "A" (sender) is too long, the transport layer will divide it in segments (called segmentation process) to understand well and not make a mistake while sending the data to "B" (recipient). After this process data is travelling through the network to the "B" (recipient), if the sent data is segmented or divided, the transport layer is responsible for reassemble it again and "B" (recipient) receives its requested data (It can be web page or other data).
  • If the transport layer will not do the segmentation process, then the next - network layer - will check the data and if the requested message is too long it will fragment it (called fragmentation process) and will provide the same as transport layer had to do.
  • All the layers processes are connected to each other and work cooperatively.
5 0
3 years ago
What is the velocity of a 0.100kg car with a momentum of 5 kgm/s?
Cerrena [4.2K]

Answer:

v = 50 m/s

Explanation:

p = mv

5 = 0.1v

v = 50

4 0
2 years ago
A two-dimensional array of characters can contain Group of answer choices
Ber [7]

Answer: All of these.

Explanation:   Lets take a two-dimensional array alphabet[4][4]

Lets say this array contains the following elements: Example 1

a b c d

l  i  o  n

f e  l   l

s t  e  m

These are the strings with same length. So this 2D array can contain strings of same length.

Now lets take another 2D array Example 2

a b c

h  i  n  t

s  o

e g  g

2D array can have all these above mentioned elements. So it can contain strings of different lengths.

Now consider the Example 2. Some places for the elements are left. This isn't an issue for 2D array. So it can contain uninitialized elements too.

So the answer is All of above.

6 0
3 years ago
Write a for loop that computes the following sum: 5+10+15+20+...+485+490+495+500. The sum should be placed in a variable sum tha
Strike441 [17]

Answer:

public class num9 {

   public static void main(String[] args) {

       int sum =0;

       int num =5;

       for(num =5; num<=500; num+=5){

           System.out.println(num);

           sum +=num;

       }

       System.out.println(sum);

   }

}

Explanation:

  • Declare and initialize the variables sum and num
  • Use a for loop with the condition for(num =5; num<=500; num+=5) Since the loop will increment by 5 and run from 5 to 500
  • Within the loop, add num to sum at each iteration
  • Print all elements on seperate lines
  • Outside the loop, print the final value of sum

Create a for loop

6 0
3 years ago
A file that is 242 megabytes is being downloaded. if the download is 15.4% complete, how many megabytes have been downloaded? ro
Lunna [17]
37.26 megabytes have been downloaded
5 0
3 years ago
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