At 7 pm, the temperature was 66*F
Temp = 78 - 3x where x = number of hours
78 - 3(7-3)
78 - 12 = 66
The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
Answer:
212018
Step-by-step explanation:
that + that + that - that times that equals 212018
hope you understood
Answer:
The measure of angle B is 68° and the measure of angle C is 22°
Step-by-step explanation:
we know that
If two angles are complementary, then their sum is equal to 90 degrees
m∠B+m∠C=90° -----> equation A
m∠B=3(m∠C)+2 ----> equation B
Substitute equation B in equation A and solve for m∠C
3(m∠C)+2+m∠C=90
4(m∠C)=90-2
4(m∠C)=88
m∠C=88/4
m∠C=22°
Find the value of m∠B
m∠B=3(22)+2=68°
therefore
The measure of angle B is 68° and the measure of angle C is 22°
