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3 years ago

B. Jennifer needs new trim around the base boards.

Mathematics

1 answer:

NeTakaya3 years ago

4 0

Is there a picture because I dont see it

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Please helpppppppppppppppppppp meeeeeeeeeeeeeeeeeeeeee

DaniilM [7]

Answer:1 page

Step-by-step explanation:

Divide

8 0

3 years ago

What is 1200 x 1200?<br><br> (this is just becouse i was bored) <br> Plz answer me <br> thx

lawyer [7]

Answer:

$\tt{}1.440.000 \\$

Step-by-step explanation:

$\tt{}1.200 \times 1.200 \: \: \: \: \: \: \: \: \: \: \\ \\ \tt{}((12 \times 12) + (0000)) \\ \\ 1.440.000 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \\$

3 0

2 years ago

In a college library there are 4 times as many nonfiction books as fiction books. How many times the number of nonfiction books

balu736 [363]

Four? Isn't it stated in the question? Unless I am assuming wrong.

8 0

3 years ago

Read 2 more answers

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

Find the distance points (7,-2) (3,1)

grandymaker [24]

Answer:

square root of 25

Step-by-step explanation:

I used my ti-84 plus ce calculator to solve

>download DISTMID

>prgm

>DISTMID

>DISTENCE

>enter points

>answer

3 0

3 years ago