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3 years ago

What is the meassure of XYZ in the diagram below HELP ASSAP :)

Mathematics

2 answers:

yaroslaw [1]3 years ago

8 0

39° or B that should be it

mihalych1998 [28]3 years ago

7 0

B. 39 degree

I don’t know how to explain it

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Find the value of X and y from the given figure.

denis23 [38]

Answer:

y = 50

x = 80

Step-by-step explanation:

An isosceles triangle therefore has both two equal sides and two equal angles.

the 2 equal angles are y and and the one next to the 130 degree

so 180- 130 = 50

y = 50

x = 180 - 50 -50 = 80 degree

8 0

3 years ago

Read 2 more answers

A bus rental company charges $60 for booking a bus and $120 for each hour the bus is rented. A tour group pays $780 to rent a bu

Rom4ik [11]

Answer:

Step-by-step explanation:

Its really pretty easy.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"

qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that $\arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)$

Also, $-\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)$

This means our original expression is equal to:

$\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]$

Using the cosine addition formula, which states $\cos(a+b)=\cos a \cos b-\sin a \sin b$ , we get this itself is equal to:

$\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)$

Since $\sin^{2} \theta+\cos^{2} \theta=1$ , we know that:

$\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}$

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

$\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}$

3 0

2 years ago

How do you solve the quadratic equation x2+2x-15=0

vlabodo [156]

X = -5 and 3

You solve using the quadratic equation by using the formula below where the coefficients of each term are the letters in alphabetical order.

$\frac{-b +/- \sqrt{b^{2} -4ac} }{2a}$

3 0

3 years ago

What is the inverse of f(x)=x^4+7 for x>0 where function g is the inverse of function f?<br> -

Ann [662]

Answer:

$g(x) = \sqrt[4]{x-7},~ x\geq 7$

Step by step explanation:

$y= f(x) = x^4+7\\\\\text{Replace x with y and solve for y:}\\\\~~~~~~~x = y^4 +7\\\\\implies y^4 = x-7\\\\\implies y = \pm\sqrt[4]{x-7}\\\\ \implies f^{-1}(x) = \pm\sqrt[4]{x-7}$

7 0

2 years ago