A. Every month Population will increase by a factor of 0.84%.
B. Every 3 months Population will increase by a factor of 2.5%.
C. Increase in population in every 20 months is 10% + 6.72% = 16.72%.
<u>Step-by-step explanation:</u>
Here, we have number of employees in a company has been growing exponentially by 10% each year. So , If we have population as x in year 2019 , an increase of 10% in population in 2020 as
which is equivalent to
.
<u>A.</u>
For each month: We have 12 months in a year and so, distributing 10% in 12 months would be like
. ∴ Every month Population will increase by a factor of 0.84%.
<u>B.</u>
In every 3 months: We have , 12 months in a year , in order to check for every 3 months
and Now, Population increase in every 3 months is
. ∴ Every 3 months Population will increase by a factor of 2.5%.
<u>C.</u>
In every 20 months: We have , 12 months in a year in which increase in population is 10% . Left number of moths for which we have to calculate factor of increase in population is 20-12 = 8. For 1 month , there is 0.84% increase in population ∴ For 8 months , 8 × 0.84 = 6.72 %.
So , increase in population in every 20 months is 10% + 6.72% = 16.72%.
2.89-2.84 = 0.05 cent increase
0.05/2.84 = 0.0176
0.0176 = 1.8% increase
Answer:
Step-by-step explanation:
Answer:
Solution is 1 (one).
Step-by-step explanation:
- The equation
can be solved by solving first the expression in the numerator. This is done by solving
. - Then, you just have
. The negative is canceled when it appears twice, so we just have to solve
(any number divided by itself equals to one).
Answer:
See Below
Step-by-step explanation:
1) 180 ft / 6 sec
You can divide both the numerator and denominator by 6:
30 ft / 1 sec
2) 86 mi/5 hr
You can divide 86 by 5:
17.2 mi / hr
3) 83 mi / 5hr
Same as above ^
16.6 mi / hr --> 16.6 mph
4) 93 feet / 5 sec
Same as above ^^
18.6 ft/ 1 sec
5) 150 mi / 4 hr
Same as above ^^^
37.5 mi / 1 hr --> 37.5 mph