Answer:
-138
Step-by-step explanation:
Distance between midpoint and point (-100) = -100 - (-119)
= 19
Since the [distance between the midpoint and point (-100)] and the [distance between the midpoint and point A] is the same, the distance between the midpoint and point A is also 19. You already know the midpoint is at -119. Since the midpoint is lower than point (-100), point A should be lower than point (-100).
Point A = -119 - 19
Point A = -138
I'm assuming the limit is supposed to be

Multiply the numerator by its conjugate, and do the same with the denominator:

so that in the limit, we have

Factorize the first term in the denominator as

The
terms cancel, leaving you with

and the limand is continuous at
, so we can substitute it to find the limit has a value of -1/18.
Answer:
a) Kwame will not take a job in industry and not go to graduate school.
b) Yoshiko does not know Java or calculus
c) James is not young nor strong
d) Rita will not move to Oregon and Washington
Step-by-step explanation:
Negation of and is or
Negation of or is and
a) Kwame will take a job in industry or go to graduate school.
Kwame will not take a job in industry and not go to graduate school.
b) Yoshiko knows Java and calculus
Yoshiko does not know Java or calculus
c) James is young and strong
James is not young nor strong
d) Rita will move to Oregon or Washington
Rita will not move to Oregon and Washington
Hello from MrBillDoesMath!
Answer:
a) See Discussion below
b) Don't know what "m" refers to
Discussion:
Part a)
A triangle contains 180 degrees.
A + B + C = 180 (*)
where A is the angle inside the triangle.
From the diagram
B +C = 62 + 78 = 140
Substituting this in (*) gives
A + (140) = 180 => subtract 140 from both sides
A = 180 - 140 = 40
Now a line has 180 degrees so x + A = 180. But A = 40 (shown above) so x+ 40 = 180, or x = 140. That is, x = 140 - the sum of the measures of the two nonadjacent interior angles
Part b)
I can't answer this part is it is unclear what "m" refers to. Sorry.
Thank you,
MrB
Yes. Multiply length and width.