9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
__
1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
Answer:
see explanation
Step-by-step explanation:
Using the tangent and sine ratios in the right triangle EFG
tan60° =
=
=
( multiply both sides by EG )
EG × tan60° = 28 ( divide both sides by tan60° )
EG =
≈ 16.2 in ( to the nearest tenth )
--------------------------------------------------------------
sin60° =
=
=
( multiply both sides by EF )
EF × sin60° = 28 ( divide both sides by sin60° )
EF =
≈ 32.3 in ( to the nearest tenth )
Answer:
The answer is given below
Step-by-step explanation:
The question is not complete, because the function for the profit is not given but I can show you how to calculate this.
Since Mr. Wilson has a bakery and a juice bar, his total profit earned in t months would be the sum of profit from the bakery with the profit from the juice bar within t months.
Let us assume that the profit from the bakery in t months is given by:
B(t) = 2t³
while the profit from the juice bar in t months is given by:
J(t) = 
Therefore the total profit is given by:
P(t) = B(t) - J(t) = 
Answer:
Step-by-step explanation:
d= 2r
therefore the radius is 1
Answer:
Skewed right as the values decrease to the right.