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LenaWriter [7]
3 years ago
10

7. You draw a card from a poker deck, replace it, and draw

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0

Answer: it would be 1/13

Step-by-step explanation:

cluponka [151]3 years ago
5 0
1/13 is the awnser :)
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There is a bag with only red marbles and blue marbles. The probability of randomly choosing a red marble is 2 9 . There are 45 m
pogonyaev

Answer:

10 red marbles

Step-by-step explanation:

Total= 45 marbles

Probability of red= 2/9

Number of red= 45*2/9= 10

7 0
2 years ago
D) If C.P. - Rs 100, S.P. Rs 80, then loss percent​
AfilCa [17]

Step-by-step explanation:

Selling price = Rs.80

Cost price = Rs.100

here, CP > SP

Now...

Loss ( L ) = CP - SP

= RS.100 - 80

= Rs.20

Now...

loss \: percent \:  =  \frac{loss}{CP}  \times 100%

=  \frac{2000}{100}  \\

= 20 %

3 0
2 years ago
The area of a rectangular invitation card is 3/10 square foot. Given that the length of the card is 4/5 foot find its perimeter
Andrei [34K]
The perimeter would be 3/8+3/8+4/5+4/5= 2.35 or 2 7/20 square foot.
I hope this helps.
YOU'RE WELCOME :D
8 0
3 years ago
Divide. Write the quotient in the lowest terms.
oee [108]

Answer:

12/1\frac{1}{5} = 10

8 0
2 years ago
Read 2 more answers
Assume that a simple random sample has been selected from a normally distributed population. State the hypotheses, find the test
BaLLatris [955]

Solution

Hypotheses:

- The population mean is 132. In order to test the claim that the mean is 132, we should check for if the mean is not 132.

- Thus, the Hypotheses are:

\begin{gathered} H_0:\mu=132 \\ H_1:\mu\ne132 \end{gathered}

Test statistic:

- The test statistic has to be a t-statistic because the sample size (n) is less than 30.

- The formula for finding the t-statistic is:

\begin{gathered} t=\frac{\bar{X}-\mu}{\frac{s}{\sqrt{n}}} \\  \\ where, \\ \bar{X}=\text{ Sample mean} \\ \mu=\text{ Population mean} \\ s=\text{ Standard deviation} \\ n=\text{ Sample size} \end{gathered}

- Applying the formula, we have:

\begin{gathered} t=\frac{137-132}{\frac{14.2}{\sqrt{20}}} \\  \\ t=\frac{5}{3.1752} \\  \\ t\approx1.5747 \end{gathered}

Critical value:

- The critical value t-critical, is gotten by reading off the t-distribution table.

- For this, we need the degrees of freedom (df) which is gotten by the formula:

\begin{gathered} df=n-1 \\ df=20-1=19 \end{gathered}

- And then we also use the significance level of 0.1 and the fact that it is a two-tailed test to trace out the t-critical. (Note: significance level of 0.1 implies 10% significance level)

- This is done below:

- The critical value is 1.729

P-value:

- To find the p-value, we simply check the table for where the t-statistic falls.

- The t-statistic given is 1.5747. We simply check which values this falls between in the t-distribution table. It falls between 1.328 and 1.729. We can simply choose a value between 0.1 and 0.05 and multiply the result by 2 since it is a two-tailed test.

- However, we can also use a t-distribution calculator, we have:

- Thus, the p-value is 0.13183

Final Conclusion:

- The p-value is 0.13183, and comparing this to the significance level of 0.1, we can see that 0.13183 is outside the rejection region.

- Thus, the result is not significant and we fail to reject the null hypothesis

7 0
1 year ago
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