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3 years ago

Plz help for this answer

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

6 0

Answer:

wth is up with your workbook answer is 4 i think

Step-by-step explanation:

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Determine the domain and range of (g ○ f)(x) if f of x is equal to 4 over the quantity x squared minus 4 end quantity and g(x) =

lara [203]

The domain and range of a function are the possible x and y values of the function.

The domain and the range of the function is: (a) $\mathbf{D:\{x \in R|x \ne -2,2\}}$ and $\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}$

The functions are given as:

$\mathbf{f(x) = \frac{4}{x^2 - 4}}$

$\mathbf{g(x) = x + 2}$

(g o f)(x) is calculated as:

$\mathbf{(g\ o\ f)(x) = g(f(x))}$

So, we have:

$\mathbf{(g\ o\ f)(x) = \frac{4}{x^2 - 4} + 2}$

Take LCM

$\mathbf{(g\ o\ f)(x) = \frac{4 + 2x^2 - 8}{x^2 - 4} }$

$\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }$

Represent the denominator as follows, to calculate the domain

$\mathbf{x^2 - 4 \ne 0 }$

Add 4 to both sides

$\mathbf{x^2 \ne 4 }$

Take square roots of bot sides

$\mathbf{x \ne \±2 }$

Hence, the domain of the function is:

$\mathbf{D:\{x \in R|x \ne -2,2\}}$

On the graph of $\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }$ (see attachment), the function does not have a value from y = 1 to 2.

Hence, the range is:

$\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}$

Read more about domain and range at:

brainly.com/question/1632425

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Step-by-step explanation:

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3 years ago

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Does anyone know this??

STALIN [3.7K]

Hi there! The answer is C.

Explanation:
We have the following equation:

$\frac{8}{15} = \frac{x}{6}$
To solve this type of equation (with an x in the denominator of a fraction) we must cross-multiply the numerator and the denominator.

$15 \times x = 8 \times 6$
Multiply

$15x = 40$
Divide both sides by 15.

$x = \frac{40}{15} = 2 \frac{2}{3}$
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3 people sharing 1/2 quart of milk equally. What fraction of a quart of milk are they sharing

bija089 [108]

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