Answer:
f(2) = 12
f(x) = 7, x = -3, 1
Step-by-step explanation:
<u>a)</u>
plug in x as 2
f(x) = 2^2 + 2(2) + 4
f(x) = 4 + 4 + 4
f(x) = 12
<u>b)</u>
replace f(x) with 7
7 = x^2 + 2x + 4
x^2 + 2x - 3 (move 7 to other side)
Factor
ac: -3x^2
b: 2x
split b into 3x, -x
(x^2 -x) + (3x - 3)
↓ ↓
x(x-1) + 3(x-1)
Factor: (x-1)(x+3) = 0
Solve using Zero Product Property:
x - 1 = 0, x + 3 = 0
x = 1, x = -3
Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
The value of p that makes the given equation true is equal to: B. p = -5
<u>Given the following equation:</u>
To find a value of p that makes the given equation true:
In this exercise, you're required to determine a value of p that satisfies the given equation true such that when substituted into the equation, it has a true result or outcome.
Rearranging the equation by collecting like terms, we have:

p = -5
Find more information: brainly.com/question/3600420
Step-by-step explanation:
(2+3)(2-3)
=5×(-1)
= -5
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