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vichka [17]
3 years ago
13

Joan is H cm tall. Gill is 3 cm shorter than Joan. Write down Gill's height in terms of H

Mathematics
1 answer:
fgiga [73]3 years ago
7 0
Joan  = H 
so to get Gill's height subtract 3
Gill's height = H - 3
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Sunny_sXe [5.5K]

Answer:

Let y = f(x) be a function with an independent variable x and a dependent variable y.

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chosen x-value is said to belong to the domain of f. If there is a requirement that a y-value produced by a function

must be a real number, the following conditions are commonly checked:

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Ted is making a bread recipe that uses three 1/4 cups of flour and a muffin recipe that uses 2 3/4 cups of flour eggs. How much
wlad13 [49]

Amount of flour used in bread recipe = 3 \frac{1}{4} cups

Amount of flour used in muffin recipe = 2 \frac{3}{4} cups

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Since, more amount of flour is used in bread recipe than in muffin recipe.

Total amount of more flour = 3 \frac{1}{4} - 2 \frac{3}{4}

= \frac{13}{4} - \frac{11}{4}

= \frac{2}{4}

= \frac{1}{2}

Therefore, \frac{1}{2} more cup of flour is used in bread recipe than in muffin recipe.

Now, we will determine the total amount of flour used in both recipe.

Total amount of flour used in bread and muffin recipe

= 3 \frac{1}{4} + 2 \frac{3}{4}

= \frac{13}{4} + \frac{11}{4}

=\frac{24}{4}

= 6 cups

Therefore, total 6 cups of flour are used in both the recipes.

3 0
3 years ago
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The formula for perimeter is:

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Therefore l is:

l = (2/3) w = 24 cm

 

<span>Hence the dimension should be 24cm by 36 cm</span>

6 0
3 years ago
Multiply<br> 5x107 * 3x105
djverab [1.8K]

Answer:

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Find the extremum of f(x,y) subject to the given constraint, and state whether it is a maximum or a minimum. f(x,y)=4x2 2y2; 3x
nevsk [136]

For given f(x, y) the extremum: (12, 24) which is the minimum.

For given question,

We have been given a function f(x) = 4x² + 2y² under the constraint 3x+3y= 108

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g(x, y) = 3x + 3y

We then take all the partial derivatives which will be needed for the Lagrange multiplier equations:

f_x=8x

f_y=4y

g_x=3

g_y=3

Setting up the Lagrange multiplier equations:

f_x=\lambda g_x

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f_y=\lambda g_y

⇒ 4y = 3λ                                         ......................(2)

constraint: 3x + 3y = 108                .......................(3)

Taking (1) / (2), (assuming λ ≠ 0)

⇒ 8x/4y = 1

⇒ 2x = y

Substitute this value of y in equation (3),

⇒ 3x + 3y = 108

⇒ 3x + 3(2x) = 108

⇒ 3x + 6x = 108

⇒ 9x = 108

⇒ x = 12

⇒ y = 2 × 12

⇒ y = 24

So, the saddle point (critical point) is (12, 24)

Now we find the value of f(12, 24)

⇒ f(12, 24) = 4(12)² + 2(24)²

⇒ f(12, 24) = 576 + 1152

⇒ f(12, 24) = 1728                             ................(1)

Consider point (18,18)

At this point the value of function f(x, y) is,

⇒ f(18, 18) = 4(18)² + 2(18)²

⇒ f(18, 18) = 1296 + 648

⇒ f(18, 18) = 1944                            ..............(2)

From (1) and (2),

1728 < 1944

This means, given extremum (12, 24) is minimum.

Therefore, for given f(x, y) the extremum: (12, 24) which is the minimum.

Learn more about the extremum here:

brainly.com/question/17227640

#SPJ4

6 0
2 years ago
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